Circular Disk Rotating About Its Diameter
The moment of inertia for the same circular disk rotating about an axis in the plane of the disk, passing through its center, is given by
![$\displaystyle I = \frac{M}{\pi R^2}\cdot 4\int_0^{\pi/2} \int_0^R [r\cos(\theta)]^2\, r\,dr\,d\theta
= \frac{1}{4}MR^2
$](http://www.dsprelated.com/josimages_new/pasp/img2728.png)
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Circular Disk Rotating in Its Own Plane
