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Force or Pressure Waves at a Rigid Termination

To find out how force or pressure waves recoil from a rigid termination, we may convert velocity waves to force or velocity waves by means of the Ohm's law relations of Eq.$ \,$(6.6) for strings (or Eq.$ \,$(6.7) for acoustic tubes), and then use Eq.$ \,$(6.12), and then Eq.$ \,$(6.6) again:

\begin{eqnarray*}
f^{{+}}(n) &=&Rv^{+}(n) \eqsp -Rv^{-}(n) \eqsp f^{{-}}(n) \\
...
...+N/2) &=&-Rv^{-}(n+N/2) \eqsp Rv^{+}(n-N/2) \eqsp f^{{+}}(n-N/2)
\end{eqnarray*}

Thus, force (and pressure) waves reflect from a rigid termination with no sign inversion:7.3

\begin{eqnarray*}
f^{{+}}(n) &=& f^{{-}}(n) \\
f^{{-}}(n+N/2) &=& f^{{+}}(n-N/2)
\end{eqnarray*}

The reflections from a rigid termination in a digital-waveguide acoustic-tube simulation are exactly analogous:

\begin{eqnarray*}
p^+(n) &=& p^-(n) \\
p^-(n+N/2) &=& p^+(n-N/2)
\end{eqnarray*}

Waveguide terminations in acoustic stringed and wind instruments are never perfectly rigid. However, they are typically passive, which means that waves at each frequency see a reflection coefficient not exceeding 1 in magnitude. Aspects of passive ``yielding'' terminations are discussed in §C.11.


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Next: Moving Rigid Termination

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About the Author: Julius Orion Smith III
Julius Smith's background is in electrical engineering (BS Rice 1975, PhD Stanford 1983). He is presently Professor of Music and Associate Professor (by courtesy) of Electrical Engineering at Stanford's Center for Computer Research in Music and Acoustics (CCRMA), teaching courses and pursuing research related to signal processing applied to music and audio systems. See http://ccrma.stanford.edu/~jos/ for details.


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