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Kinetic Energy of a Mass

From Newton's second law, $ f=ma=m{\ddot x}$ (introduced in Eq.$ \,$(F.1)), we can derive the formula for the kinetic energy of a mass given its speed $ v={\dot x}$. Let $ d x$ denote a small (infinitesimal) displacement of the mass in the $ x$ direction. Then we have, using the calculus of differentials,

\begin{eqnarray*}
f(t) &=& m\, {\ddot x}\\
\,\,\Rightarrow\,\,\quad d W\isdef f...
...c{1}{2}{\dot x}^2\right)\\
&=& d\left(\frac{1}{2}m\,v^2\right).
\end{eqnarray*}

Thus, by Newton's second law, a differential of work $ dW$ applied to a mass $ m$ by force $ f$ through distance $ d x$ boosts the kinetic energy of the mass by $ d(m\,v^2/2)=m\,v\,dv=ma\,dx$. Therefore, we must have

$\displaystyle E_m(t) = \frac{1}{2}m v^2(t) = \frac{1}{2}{\dot x}^2(t),
$

where $ E_m(t)$ denotes the kinetic energy of the mass $ m$ traveling at speed $ v(t)$ at time $ t$.

The quantity $ dW=f\,dx$ is classically called the virtual work associated with force $ f$, and $ d x$ a virtual displacement [560].


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written by Julius Orion Smith III
Julius Smith's background is in electrical engineering (BS Rice 1975, PhD Stanford 1983). He is presently Professor of Music and Associate Professor (by courtesy) of Electrical Engineering at Stanford's Center for Computer Research in Music and Acoustics (CCRMA), teaching courses and pursuing research related to signal processing applied to music and audio systems. See http://ccrma.stanford.edu/~jos/ for details.


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