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Parallel Axis Theorem

For an area $ A$ whose centroidal axis is displaced $ d$ from the axis of rotation along $ x$, the moment of inertia about the $ x$ axis is given by

$\displaystyle I_x(d) = I_x(0) + Md^2
$

where $ M$ denotes the total rotating mass, and $ I_x(0)$ is defined as the moment of inertia of area $ A$ about its centroidal axis parallel to the $ x$ axis. Thus, the added inertia due to displacement by $ d$ meters from the centroidal axis is equal to that of a point mass $ M$ rotating a distance $ d$ from the center of rotation.


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written by Julius Orion Smith III
Julius Smith's background is in electrical engineering (BS Rice 1975, PhD Stanford 1983). He is presently Professor of Music and Associate Professor (by courtesy) of Electrical Engineering at Stanford's Center for Computer Research in Music and Acoustics (CCRMA), teaching courses and pursuing research related to signal processing applied to music and audio systems. See http://ccrma.stanford.edu/~jos/ for details.


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