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Can someone help me understand how to calculate what frequency is output from the quad timer. After playing around with numbers i eventually came up with the following solution to obtain a 10KHz square wave, but dont know how this could have been calculated. I set the PLL_DIVIDE_BY REG in appconfig.h to 0x00B0 I then used these parameters in main function const qt_sState quadParam1 = { /* Mode = */ qtCount, /* InputSource = */ qtPrescalerDiv1, /* InputPolarity = */ qtNormal, /* SecondaryInputSource = */ 0, /* CountFrequency = */ qtRepeatedly, /* CountLength = */ qtUntilCompare, /* CountDirection = */ qtUp, /* OutputMode = */ qtToggleOnCompare, /* OutputPolarity = */ qtNormal, /* OutputDisabled = */ 0, /* Master = */ 0, /* OutputOnMaster = */ 0, /* CoChannelInitialize = */ 0, /* AssertWhenForced = */ 0, /* CaptureMode = */ qtDisabled, /* CompareValue1 = */ 0x977, //generates 10KHz /* CompareValue2 = */ 0, /* InitialLoadValue = */ 0, /* CallbackOnCompare = */ { 0, 0 }, /* CallbackOnOverflow = */ { 0, 0 }, /* CallbackOnInputEdge = */ { 0, 0 } }; Why have these settings generated a 10KHZ clock?

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Hi CJ, It's not real easy. The first question I would ask is where you came up with the value of 0x00B0 for the pll divide reg. From what I can see that value will put the PLL at a frequency that is way beyond it's recommended operating parameters (See DSP56F80X User's Manual, Chapter 15 On Chip Clock Synthesis, Section 15.6.12). To run the normal 80MHz frequency a value of 0x0013 (19) would be used in the PLL divide reg. This gives a 40MHz IP_BUS frequency which drives the quad timer inputs. It is calculated by (8MHz * (19+1) / 2 / 2)= IP_BUS freq. or (crystal * (PLLDB+1) / Div2 / Div2)= IP_BUS freq. Figure 15-14 shows a good layout of how that is derived. When you know your input frequency (IP_BUS) you can set the values in the qt_sState structure to get your desired freq. -With qtPrescalerDiv1 you still have IP_BUS (40MHz if using 19) clocking the timer. -Using 'toggle on compare' (qtRepeatedly, qtUntilCompare, qtToggleOnCompare, qtUp) your output frequency will be 1/2 the toggle frequency which is the input freq divided by the compare value OR (IP_BUS / CompareValue1 / 2) = Output Freq. (40MHz / 2000 / 2) = 10khz Hope this Helps. Pete --- In , "TA1T" <cj_tait@h...> wrote: > > Can someone help me understand how to calculate what frequency is > output from the quad timer. After playing around with numbers i > eventually came up with the following solution to obtain a 10KHz > square wave, but dont know how this could have been calculated. > I set the PLL_DIVIDE_BY REG in appconfig.h to 0x00B0 > I then used these parameters in main function > > const qt_sState quadParam1 = { > > /* Mode = */ qtCount, > /* InputSource = */ qtPrescalerDiv1, > /* InputPolarity = */ qtNormal, > /* SecondaryInputSource = */ 0, > > /* CountFrequency = */ qtRepeatedly, > /* CountLength = */ qtUntilCompare, > /* CountDirection = */ qtUp, > > /* OutputMode = */ qtToggleOnCompare, > /* OutputPolarity = */ qtNormal, > /* OutputDisabled = */ 0, > > /* Master = */ 0, > /* OutputOnMaster = */ 0, > /* CoChannelInitialize = */ 0, > /* AssertWhenForced = */ 0, > > /* CaptureMode = */ qtDisabled, > > /* CompareValue1 = */ 0x977, //generates 10KHz > /* CompareValue2 = */ 0, > /* InitialLoadValue = */ 0, > > /* CallbackOnCompare = */ { 0, 0 }, > /* CallbackOnOverflow = */ { 0, 0 }, > /* CallbackOnInputEdge = */ { 0, 0 } > }; > Why have these settings generated a 10KHZ clock?

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