The second one should be faster because matrix A is pre-alocated.
Je
Reply by V Ravi Chander●April 15, 20052005-04-15
hi cal,
if 'b' is the 1X5 vector generated inside the for loop, and
'a' is the
10X5 matrix that you need,
for i=1:10
%some processing to obtain b
a(i,:)=b;
%or a=[a;b];
end
regards,
Ravi
>
> Hi
>
> Could somebody please help.
>
> Inside a loop I generate a (1X5)vector. At each step I want to
> include this vector as a new row of a matrix. So, for example, after
> 10 times through the loop I will have generated a (10X5) matrix.
>
> Is there a quick way of doing this?
>
> Any help would be much appreciated.
>
> Thanks
>
> Cal
>
--
V Ravi Chander,
Emerging Technologies and Services Group,
Reliance Infocomm Ltd.
Reply by camdmag●April 14, 20052005-04-14
Hi
Could somebody please help.
Inside a loop I generate a (1X5)vector. At each step I want to
include this vector as a new row of a matrix. So, for example, after
10 times through the loop I will have generated a (10X5) matrix.