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I am trying to implement J.17 de-emphasis cure in a 32 bit processor.
I have converted J.17 S-domain transfer function using Bilinear of
MATLAB. The maltlab plot of manitude responce matches with the table
biven in the std. But when i verify in Audio precession I get +5dB
error in the range of 2-4 Khz. I have implemented in Directform 2 type
filter. Does nay body has idea why i am getting this difference..?
Regards

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On Fri, 16 Jan 2004 02:33:36 +0000, Anand wrote:

> I am trying to implement J.17 de-emphasis cure in a 32 bit processor.
> I have converted J.17 S-domain transfer function using Bilinear of
> MATLAB. The maltlab plot of manitude responce matches with the table
> biven in the std. But when i verify in Audio precession I get +5dB
> error in the range of 2-4 Khz. I have implemented in Directform 2 type
> filter. Does nay body has idea why i am getting this difference..?
> Regards


Give me figures. S and Z transform equations

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"Robin Clark" <r...@hotTEETHmail.com> wrote in message
news:<p...@hotTEETHmail.com>...
> On Fri, 16 Jan 2004 02:33:36 +0000, Anand wrote:
> 
> > I am trying to implement J.17 de-emphasis cure in a 32 bit processor.
> > I have converted J.17 S-domain transfer function using Bilinear of
> > MATLAB. The maltlab plot of manitude responce matches with the table
> > biven in the std. But when i verify in Audio precession I get +5dB
> > error in the range of 2-4 Khz. I have implemented in Directform 2 type
> > filter. Does nay body has idea why i am getting this difference..?
> > Regards
> 
> 
> Give me figures. S and Z transform equations

Hi,
As per J.17 std 
Insertion Loss between nominal Impedences = 10log10
75+(w/3000)^2/1+(w/3000)^2
That gives
H(s) = s-(75)^1/2 * 3000/s-3000;
Normalizing with 18.75 dB ( gain at 0Hz as per J.17) and converting
into Z gives me

H(z) = 0.1423 - 0.0817 z^-1/1-0.9394 z^-1

Both my s and z domain plots match in MATLAB, 
After implementing in 32 fixed point processor i get 5db differance as
i move to frequencies above 2k hz  ...!!
Anand

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"Robin Clark" <r...@hotTEETHmail.com> wrote in message
news:<p...@hotTEETHmail.com>...
> On Fri, 16 Jan 2004 02:33:36 +0000, Anand wrote:
> 
> > I am trying to implement J.17 de-emphasis cure in a 32 bit processor.
> > I have converted J.17 S-domain transfer function using Bilinear of
> > MATLAB. The maltlab plot of manitude responce matches with the table
> > biven in the std. But when i verify in Audio precession I get +5dB
> > error in the range of 2-4 Khz. I have implemented in Directform 2 type
> > filter. Does nay body has idea why i am getting this difference..?
> > Regards
> 
> 
> Give me figures. S and Z transform equations

Hi,
As per J.17 std 
Insertion Loss between nominal Impedences = 10log10
75+(w/3000)^2/1+(w/3000)^2
That gives
H(s) = s-(75)^1/2 * 3000/s-3000;
Normalizing with 18.75 dB ( gain at 0Hz as per J.17) and converting
into Z gives me

H(z) = 0.1423 - 0.0817 z^-1/1-0.9394 z^-1

Both my s and z domain plots match in MATLAB, 
After implementing in 32 fixed point processor i get 5db differance as
i move to frequencies above 2k hz  ...!!
Anand

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Anand wrote:

> "Robin Clark" <r...@hotTEETHmail.com> wrote in message
news:<p...@hotTEETHmail.com>...
> 
>>On Fri, 16 Jan 2004 02:33:36 +0000, Anand wrote:
>>
>>
>>>I am trying to implement J.17 de-emphasis cure in a 32 bit processor.
>>>I have converted J.17 S-domain transfer function using Bilinear of
>>>MATLAB. The maltlab plot of manitude responce matches with the table
>>>biven in the std. But when i verify in Audio precession I get +5dB
>>>error in the range of 2-4 Khz. I have implemented in Directform 2 type
>>>filter. Does nay body has idea why i am getting this difference..?
>>>Regards
>>
>>
>>Give me figures. S and Z transform equations
> 
> 
> Hi,
> As per J.17 std 
> Insertion Loss between nominal Impedences = 10log10
> 75+(w/3000)^2/1+(w/3000)^2
> That gives
> H(s) = s-(75)^1/2 * 3000/s-3000;
> Normalizing with 18.75 dB ( gain at 0Hz as per J.17) and converting
> into Z gives me
> 
> H(z) = 0.1423 - 0.0817 z^-1/1-0.9394 z^-1
> 
> Both my s and z domain plots match in MATLAB, 
> After implementing in 32 fixed point processor i get 5db differance as
> i move to frequencies above 2k hz  ...!!
> Anand

Whoa! 10log10 is for power. For voltage, you need 20log10. Start there, 
and you'll get 10 dB at the end.

Jerry
-- 
Engineering is the art of making what you want from things you can get.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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Jerry Avins <j...@ieee.org> wrote in message news:<400bf6c5$0$6083$6...@news.rcn.com>...
> Anand wrote:
> 
> > "Robin Clark" <r...@hotTEETHmail.com> wrote in message
news:<p...@hotTEETHmail.com>...
> > 
> >>On Fri, 16 Jan 2004 02:33:36 +0000, Anand wrote:
> >>
> >>
> >>>I am trying to implement J.17 de-emphasis cure in a 32 bit processor.
> >>>I have converted J.17 S-domain transfer function using Bilinear of
> >>>MATLAB. The maltlab plot of manitude responce matches with the table
> >>>biven in the std. But when i verify in Audio precession I get +5dB
> >>>error in the range of 2-4 Khz. I have implemented in Directform 2 type
> >>>filter. Does nay body has idea why i am getting this difference..?
> >>>Regards
> >>
> >>
> >>Give me figures. S and Z transform equations
> > 
> > 
> > Hi,
> > As per J.17 std 
> > Insertion Loss between nominal Impedences = 10log10
> > 75+(w/3000)^2/1+(w/3000)^2
> > That gives
> > H(s) = s-(75)^1/2 * 3000/s-3000;
> > Normalizing with 18.75 dB ( gain at 0Hz as per J.17) and converting
> > into Z gives me
> > 
> > H(z) = 0.1423 - 0.0817 z^-1/1-0.9394 z^-1
> > 
> > Both my s and z domain plots match in MATLAB, 
> > After implementing in 32 fixed point processor i get 5db differance as
> > i move to frequencies above 2k hz  ...!!
> > Anand
> 
> Whoa! 10log10 is for power. For voltage, you need 20log10. Start there, 
> and you'll get 10 dB at the end.
> 
> Jerry
Hi, 
I don't use this log part to compute the transfer function. I get it
by substituting s= jw , in the equetion given in J.17 std.
Can you be more elobarate on this...
Regards
Anand

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Anand wrote:

  ...

> Hi, 
> I don't use this log part to compute the transfer function. I get it
> by substituting s= jw , in the equetion given in J.17 std.
> Can you be more elobarate on this...
> Regards
> Anand

Steer me to J.17 so I can see what it says. Maybe I didn't understand
the problem. A Z transform implies a sampling rate. For a detailed look
at your results, I need to know what it is. Remember: you can expect the
actual response to depart considerably from the continuous prototype's
as you approach fs/2.

Jerry
-- 
Engineering is the art of making what you want from things you can get.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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Jerry Avins <j...@ieee.org> wrote in message news:<400d5661$0$15631$6...@news.rcn.com>...
> Anand wrote:
> 
>   ...
> 
> > Hi, 
> > I don't use this log part to compute the transfer function. I get it
> > by substituting s= jw , in the equetion given in J.17 std.
> > Can you be more elobarate on this...
> > Regards
> > Anand
> 
> Steer me to J.17 so I can see what it says. Maybe I didn't understand
> the problem. A Z transform implies a sampling rate. For a detailed look
> at your results, I need to know what it is. Remember: you can expect the
> actual response to depart considerably from the continuous prototype's
> as you approach fs/2.
> 
> Jerry

Hi,
In the previous posting i have puts the J.17 std details. The transferfunction etc..

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Anand wrote:

   ...
> 
> Hi,
> In the previous posting i have puts the J.17 std details. The transferfunction etc..

Do you mean
"Insertion Loss between nominal Impedences = 10log10
75+(w/3000)^2/1+(w/3000)^2
That gives
H(s) = s-(75)^1/2 * 3000/s-3000;" ?

What does "Insertion Loss between nominal Impedences" mean? What are 
those impedances? 10log10 of what? Of 75+(w/3000)^2/1+(w/3000)^2?
I wanted to see the document you pulled those from so I could understand 
your need well enough to help. I don't understand the problem.

Jerry
-- 
Engineering is the art of making what you want from things you can get.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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