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hi I'm a bit screwed up by the notation used in fourier transform, on convolution and product theorems. I'm drawing a blank with regard to what's the difference between: f1(t)*f2(t) <=> F1(w)F2(w) [convolution theorem] f1(t)f2(t) <=> F1(w)*F2(w) [product theorem] what's the difference between "f1(t)*f2(t)" and "f1(t)f2(t)" please give one example. Thanks.______________________________
p...@yahoo.ca wrote: > hi > > I'm a bit screwed up by the notation used in fourier transform, on > convolution and product theorems. I'm drawing a blank with regard to > what's the difference between: > f1(t)*f2(t) <=> F1(w)F2(w) [convolution theorem] > f1(t)f2(t) <=> F1(w)*F2(w) [product theorem] > what's the difference between "f1(t)*f2(t)" and "f1(t)f2(t)" > please give one example. In that notation, "*" indicates convolution, not multiplication. Jerry -- Engineering is the art of making what you want from things you can get. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯______________________________
Jerry Avins wrote: > p...@yahoo.ca wrote: > > hi > > > > I'm a bit screwed up by the notation used in fourier transform, on > > convolution and product theorems. I'm drawing a blank with regard to > > what's the difference between: > > f1(t)*f2(t) <=3D> F1(w)F2(w) [convolution theorem] > > f1(t)f2(t) <=3D> F1(w)*F2(w) [product theorem] > > what's the difference between "f1(t)*f2(t)" and "f1(t)f2(t)" > > please give one example. > > In that notation, "*" indicates convolution, not multiplication. "*" meaning "Convolution" in both theorem? > > Jerry > -- > Engineering is the art of making what you want from things you can get. > =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF= =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF= =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF______________________________
p...@yahoo.ca wrote: > Jerry Avins wrote: >> p...@yahoo.ca wrote: >>> hi >>> >>> I'm a bit screwed up by the notation used in fourier transform, on >>> convolution and product theorems. I'm drawing a blank with regard to >>> what's the difference between: >>> f1(t)*f2(t) <=> F1(w)F2(w) [convolution theorem] >>> f1(t)f2(t) <=> F1(w)*F2(w) [product theorem] >>> what's the difference between "f1(t)*f2(t)" and "f1(t)f2(t)" >>> please give one example. >> In that notation, "*" indicates convolution, not multiplication. > > "*" meaning "Convolution" in both theorem? > Yes, exactly that. You can state it as: 1) Convolution in the time domain is equivalent to multiplication in the fourier domain. 2) Multiplication in the time domain is equivalent to convolution in the fourier domain. These statements change a little in discrete systems, but your use of t suggests that you are concerned with the continuous case. If you want to understand the difference between convolution and multiplication, a text book with good diagrams is probably the best place to look. Cheers Marc______________________________
p...@yahoo.ca skrev: > hi > > I'm a bit screwed up by the notation used in fourier transform, on > convolution and product theorems. I'm drawing a blank with regard to > what's the difference between: > f1(t)*f2(t) <=> F1(w)F2(w) [convolution theorem] > f1(t)f2(t) <=> F1(w)*F2(w) [product theorem] > what's the difference between "f1(t)*f2(t)" and "f1(t)f2(t)" f(n)*g(n) represents convolution. You can also see this as f(n)(*)g(n) if one wants to emphasize that '*' has nothing to do with the ususal product. > please give one example. Assume the sequences f(n) = ...,0,0,|1,2,3,2,1,0,0,... g(n)= ...,0,0,|1,1,1,1,1,0,0,... where the bar | indicates n = 0. Then f(n)g(n) = ...,0,0,|1,2,3,2,1,0,0,... f(n)(*)g(n) = ...,0,0,|1,3,6,8,9,8,6,3,1,0,0,... Rune______________________________
<p...@yahoo.ca> escribió en el mensaje news:1...@79g2000cws.googlegroups.com... > hi > > I'm a bit screwed up by the notation used in fourier transform, on > convolution and product theorems. I'm drawing a blank with regard to > what's the difference between: > f1(t)*f2(t) <=> F1(w)F2(w) [convolution theorem] > f1(t)f2(t) <=> F1(w)*F2(w) [product theorem] > what's the difference between "f1(t)*f2(t)" and "f1(t)f2(t)" > please give one example. > > Thanks. The * stands for convolution, not multiplication (or product, so to speak). -- Posted via a free Usenet account from http://www.teranews.com______________________________