Recent thread on RFFT

Started by Eric in comp.dsp60 minutes ago 10 replies

I read through part of the recent thread on FFT's for FPGAs. Interestng comments on optimization. Is the real vs complex issue covered in any...

I read through part of the recent thread on FFT's for FPGAs. Interestng comments on optimization. Is the real vs complex issue covered in any notable texts? I would not have thought that it would afford any significant advantage in runtime. I'm not so interested in FPGAs.as in whether there are methods that are generally accepted as close to optimal for a -windowed- FFT/STFT, assuming th...


Sorry about the many posts

Started by Michael Plet in comp.dsp4 hours ago 1 reply

Hi Group I'm sorry about posting all my formulas without any delay. I just wanted to get them out there while they are new, so that...

Hi Group I'm sorry about posting all my formulas without any delay. I just wanted to get them out there while they are new, so that other people can use them if they want. Michael Plet


EZ KIT LITES USB DRIVER/WINDOWS XP

Started by bambou in comp.dsp5 hours ago 1 reply

Hi everybody, I am looking for a EZ KIT LITES USB DRIVER for WINDOWS XP, i am still using windows xp with visual...

Hi everybody, I am looking for a EZ KIT LITES USB DRIVER for WINDOWS XP, i am still using windows xp with visual dsp. --------------------------------------- Posted through http://www.DSPRelated.com


Plet's Fifth Estimator

Started by Michael Plet in comp.dsp11 hours ago

Hi Group This is a new estimator based on the magnitudes of three DFT bins. The estimator is exact for a pure sinusoid without noise. It...

Hi Group This is a new estimator based on the magnitudes of three DFT bins. The estimator is exact for a pure sinusoid without noise. It performs well in the presence of noise. Let j be the index of the DFT bin with the largest magnitude. Let k=j-1 and i=j+1. Now let Ck = Cos(2*PI*k/N) Cj = Cos(2*PI*j/N) Ci = Cos(2*PI*i/N) Then the Cosine of the normalised angular frequency can...


Ooooh, trippy! But I think my house is haunted

Started by Tim Wescott in comp.dsp12 hours ago 17 replies

My wife's been after me for decades to get my hearing tested. I've resisted until now because only old people need hearing aids. Turns out...

My wife's been after me for decades to get my hearing tested. I've resisted until now because only old people need hearing aids. Turns out that I have a hearing loss pattern that's typical of congenital hearing loss. I had thought it was from too many model airplane motors in my youth. On reflection, it's consistent with my Dad's hearing loss, which _he_ attributed to ear surgery whe...


Plet's Fourth Estimator

Started by Michael Plet in comp.dsp1 day ago

Hi Group This is a new estimator based on the imaginary values of three DFT bins. The estimator is exact for a pure sinusoid without...

Hi Group This is a new estimator based on the imaginary values of three DFT bins. The estimator is exact for a pure sinusoid without noise. It performs well in the presence of noise. Let j be the index of the DFT bin with the largest magnitude. Let k=j-1 and i=j+1. Now let Sk = Sin(2*PI*k/N) Ck = Cos(2*PI*k/N) Sj = Sin(2*PI*j/N) Cj = Cos(2*PI*j/N) Si = Sin(2*PI*i/N) Ci = Cos(2...


Plet's Third Estimator

Started by Michael Plet in comp.dsp2 days ago

Hi Group This is a new estimator based on the real values of three DFT bins. The estimator is exact for a pure sinusoid without noise. It...

Hi Group This is a new estimator based on the real values of three DFT bins. The estimator is exact for a pure sinusoid without noise. It performs well in the presence of noise. Let j be the index of the DFT bin with the largest magnitude. Let k=j-1 and i=j+1. Now let Sk = Sin(2*PI*k/N) Ck = Cos(2*PI*k/N) Sj = Sin(2*PI*j/N) Cj = Cos(2*PI*j/N) Si = Sin(2*PI*i/N) Ci = Cos(2*PI*i/...


Plet's Second Estimator

Started by Michael Plet in comp.dsp1 week ago 2 replies

Hi Group This is a new estimator based on real and imaginary values of two DFT bins. The estimator is exact for a pure sinusoid without...

Hi Group This is a new estimator based on real and imaginary values of two DFT bins. The estimator is exact for a pure sinusoid without noise. It performs well in the presence of noise. Let k be the index of the DFT bin with the largest magnitude. Let j be the index of the DFT bin with the largest magnitude neigboring bin k. That is j=k-1 or j=k+1. Now let Sk = Sin(2*PI*k/N) Ck ...


Searching for fixed point g.728 sources

Started by Anonymous in comp.dsp2 weeks ago 7 replies

I am searching for a Fixed Point C implementation of G.728 codec. Can anyone point me to it's free version or sell it to me? Thanks.

I am searching for a Fixed Point C implementation of G.728 codec. Can anyone point me to it's free version or sell it to me? Thanks.


New frequency estimator from two DFT bins

Started by Michael Plet in comp.dsp2 weeks ago 22 replies

Hi Group I have derived this estimator. The limited tests I have done shows high accuracy. Let k be the index of the DFT bin with the...

Hi Group I have derived this estimator. The limited tests I have done shows high accuracy. Let k be the index of the DFT bin with the largest magnitude. Let j be the index of the DFT bin with the largest magnitude neigboring bin k. That is j=k-1 or j=k+1. Now let P=Tan(PI*k/N) and Q=Tan(PI*j/N) Then the normalized frequency is estimated by: Freq=(N/PI)*Arctan(Sqr(P*Q*(Im[k]*P...


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