Hi, Martin.
If I seem a bit more confused than usual it's because I'm
alternating writing my reply with a periodic background sampling
process: "The Effects of Extended Hurricane-Based Rainfall on
Mostly-Impermeable Cinder Block Basement Walls". The good news is
that my sampling device (a.k.a. "ShopVac") has a 16 gallon buffer.
On 5 Sep 2008 15:33:20 GMT, Martin Eisenberg <martin.eisenberg@udo.edu> wrote:
> Frnak McKenney wrote:
>
>>>> Assumption: The CWT(g(),psi(),t,s) is, in some measure,
>>>> related to the Fourier "frequency" spectrum of f(). That is,
>>>> for a fixed g() and psi(), if the frequency spectrum of g()
>>>> contains some frequency f0 at time t0, then for some 'scale'
>>>> s0 the results of the CWT(g(),psi(),t0,s0) has some sort of
>>>> "peak".
>>>
>>> It has power there but that doesn't say anything about the
>>> waveform carrying it.
>>
>> "Power". As in "magnitude squared". Okay... the signal g()
>> has amplitude-hence-magnitude, and a wavelet has amplitude-hence
>> -magnitude, so even though my head hurts when I try to visualize
>> it, I can accept the idea that g()*psi() -- or, more precisely,
>> the sum/integral of g()*psi() -- represents "power".
>
> Argh no, erase that thought ;) It's nothing to do with the mechanics
> of computation! The signal has some spectrotemporal distribution of
> power as a matter of fact, and the scalogram is designed to present
> that in a recognizable way (one way among others, of course).
Okay. I misunderstood. I thought I had a handle on what the range
(output) of a CWT(scale,time) was, and my initial reading of your
reply threw me a bit.
Let me try to put my current "model" into words and see if it makes
sense:
The CWT(f(),phi(),s,tau) maps a single function/signal f() into a
_family_ of function/signals. Each member of this (possibly
infinite) family is created by repeatedly taking, at each point of
f(), an inner product of f() with a scaled copy of the wavelet
function psi() which has been translated to that point.
So the "range" of the CWT(), the "surface" the CWT describes above
the scale-time plane, is the same as the "range" of the signal(s),
that is, amplitude.
>> Another question, or at least request for confirmation. Suppose
>> I have the (infinite) CWT scale-time (y-x) plane laid out in
>> front of me, and further assume that I can stretch out a pair of
>> more-than- infinitely-extensible hands to squeeze it from the
>> top and bottom (Ack!) into a horizontal line. If my chosen
>> wavelets form an orthonormal basis (that is, they chop up
>> functions in such a way that they can be exactly reconstructed),
>> don't I get back my original function?
>
> You can imagine it that way, noting that the synthesis wavelet
> (reconstruction filterbank) gets thrown in too.
Oh. Right. I forgot that the "chopping up" involved changing the
shape of the signal "pieces" in a specific fashion (dependent on the
choice of wavelet), and therefore one would have to "undo" those
changes in order to put the "pieces" back together properly.
Hey! That actually made sense! (And who said miracles were out of
fashion? <grin!>
>> Okay, that seems fairly trivial. But... suppose I squeeze from
>> the right and left? Well, if I've left in any unbounded
>> thingies, such as sine-waves-extended-to-forever, some or all of
>> the result may blow up in my face. But ignoring that messy (but
>> very real) possibility, it "feels" like I wind up with a set of
>> values representing the "scales" at which my original function
>> had "power" at any point in time.
>>
>> What would you call it? A... "scale spectrum"?
>
> Good question; I don't know if there's an established term. But you
> could also describe it without reference to wavelets as a Fourier
> spectrum aggregated over log-spaced intervals.
After listening to your restatement, I think I just re-invented the
Constant-Q Transform in "scale" clothing. <grin!>
But the important thing (to me) is that I'm "pushing things around"
and seeing results that match what my "model" predicts.
So now I go back and re-read Hubbard and the five or six papers that
seemed to make the most sense. If I'm lucky, a few more bits will
make sense this time around.
>> Meanwhile, in TheRealWorld(tm), it appears that Murphy -- long
>> recognized as the patron saint of Data Processing -- has decided
>> to take a hand in the American Presidential Election process.
>> "May we live in interesting times", indeed. <grin!>
>
> I'm not American, you know. Does that mean you consider the election
> decided with McCain's nomination?
Not in the least. But let me explain, or at least try to. <grin!>
Every four years we hold our Presidential elections. As a part of
the process each candidate must undergo a long series of trials to
show that they are Worthy: Trial by Insult, Trial by Shaming, Trial
by Prolonged Examination in Minute Detail (a.k.a. Trial by Media),
Trial of Ideological Purity, Trial of Historical Consistency, Trial
by Slings and Arrows of Outrageous Fortune, ... well, you get the
idea. Points are deducted each time a candidate fails to stoically
endure one of their trials; points are added when they can not
merely endure a trial better/longer than an opponent, but make it
appear as if the results are unimportant to them.
Until a week ago (only one week?) it appeared that we would be
witness to the trials of four fairly similar candidates. The three
"knowns" were all legislators (two old-timers and one newcomer), and
most of us assumed that McCain's choice for VP would be yet another
Washington "insider".
McCain's selection of Governor Sarah Palin (Alaska) as his running
mate has put new life into the process. She's not well known, so
the media can spend hours discussing her without getting bored.
She's female, as governor she has experience none of the other three
have, she's conservative, she hunts and fishes, and she has
successfully fought the oil companies, so the political pundits have
plenty of material for speculating on (e.g.) what percentage of
Senator Clinton's former supporters will cross over to vote for her.
She's attractive and personable enough, and can speak coherent
sentences, so she's likely to do well on talk shows. Finally, her
personality and views have enough "edges" for easy caricature, which
makes her a prime candidate for (e.g.) Saturday Night Live.
<grin!>
Even the people who don't like her are talking about her.
As I say, "interesting times". What looked to be a fairly
predictable (hence boring) see-saw battle between the parties for
the last few independent voters has suddenly shifted into unexpected
dimensions, and this is likely to increase the voter turnout on both
sides. And since that puts the outcome of the election even more in
doubt, people (voters) are paying even more attention to the
process. <grin!>
Anyway, that's my not-so-humble opinion. Hope y'all can enjoy it
from afar.
Frank
--
The Democrats are the party of government activism, the party
that says government can make you richer, smarter, taller, and
get the chickweed out of your lawn. Republicans are the party
that says government doesn't work, and then get elected and
prove it. -- P. J. O'Rourke
--
Frank McKenney, McKenney Associates
Richmond, Virginia / (804) 320-4887
Munged E-mail: frank uscore mckenney ayut mined spring dawt cahm (y'all)