Reply by Jerry Avins March 31, 20042004-03-31
Bhaskar Thiagarajan wrote:

> "Texas Longhorns" <OUSucks@hotmail.com> wrote in message > news:V8Kac.5340$o_.5100@fe1.texas.rr.com... > >>If linear modulation systems are to be compared on an equal peak power > > basis > >>(all have equal peak signal values), show that: >>A. SSB has a (S/N)out that is 3 dB better than DSB. >>B. SSB has a (S/N)out that is 9 dB better than AM. >> >>Help with this problem would be greatly appreciated. Thank you in advance. >> > > > You'll have better luck getting help on homework problems if you showed some > effort in trying to solve it yourself...how far you got and where exactly > you are stuck. > If you have trouble even getting started, what part the problem description > baffles you? > > On this specific one... > on part A, what does a change in power of a signal by 3dB signify to you - > perhaps that'll help you get started. > > Cheers > Bhaskar
Tex, A few questions that might help you focus: 1) How does noise relate to bandwidth? 2) What components comprise your three waveforms? 3) In of those waveforms, what does S in S/N represent? 4) Is all the power in S? Jerry -- Engineering is the art of making what you want from things you can get. &#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;
Reply by Bhaskar Thiagarajan March 31, 20042004-03-31
"Texas Longhorns" <OUSucks@hotmail.com> wrote in message
news:V8Kac.5340$o_.5100@fe1.texas.rr.com...
> If linear modulation systems are to be compared on an equal peak power
basis
> (all have equal peak signal values), show that: > A. SSB has a (S/N)out that is 3 dB better than DSB. > B. SSB has a (S/N)out that is 9 dB better than AM. > > Help with this problem would be greatly appreciated. Thank you in advance. >
You'll have better luck getting help on homework problems if you showed some effort in trying to solve it yourself...how far you got and where exactly you are stuck. If you have trouble even getting started, what part the problem description baffles you? On this specific one... on part A, what does a change in power of a signal by 3dB signify to you - perhaps that'll help you get started. Cheers Bhaskar
Reply by Texas Longhorns March 31, 20042004-03-31
If linear modulation systems are to be compared on an equal peak power basis
(all have equal peak signal values), show that:
A. SSB has a (S/N)out that is 3 dB better than DSB.
B. SSB has a (S/N)out that is 9 dB better than AM.

Help with this problem would be greatly appreciated. Thank you in advance.