Sure, but the "frequency response" of a filter is the z-transform
evaluated
along the unit circle, where z = exp(j*w), w from -pi to pi. So the frequency
response is
H(w) = summation over n of h(n)*exp(j*w*n).
This is all you need to evaluate the frequency response of your filter.
Sincerely,
Glen Ragan
Reply by Appalayagari Sreedhar●November 22, 20022002-11-22
Hi,
in the implementation of the filter
H(z) = (sigma)h(n)z^-n;
is it possible to directly use this expression and obtain the frequency
response
in z domain.