Reply by navaneetha krishnan July 1, 20032003-07-01
Filtering and down sampling are not commutative.

Regards,
Navan --- egan_nc <> wrote:
> Hi,
> I designed a filter using remezord function. When I
> filtered the
> input first and downsampled later, the filter works
> fine.
> out2a=filter(h1,1,out1a);
> out2b=downsample(out2a,4);
> But when I downsampled first and then fitlered it
> later the output is
> incorrect.
> out2a=downsample(out1a,4);
> out2b=filter(h1,1,out2a);
> Any help is highly appreciated.
> Thanks,
> EngGan


__________________________________


Reply by Saiju T Joseph July 1, 20032003-07-01
The result is as expected.

For making things very clear, ask the question why do u do the filtering?

The filtering bandlimits the signal and then u downsample-----> Results
should be OK

When u downsample first there will be folding effect and the resultant
signal is corrupted by the reflection of frequencies outside our bandlimit.
From here on you are dealing with a corrupted signal.

Hope it's clear.

----- Original Message -----
From: "egan_nc" <>
To: <>
Sent: Monday, June 30, 2003 8:09 PM
Subject: [matlab] filter and downsample

> Hi,
> I designed a filter using remezord function. When I filtered the
> input first and downsampled later, the filter works fine.
> out2a=filter(h1,1,out1a);
> out2b=downsample(out2a,4);
> But when I downsampled first and then fitlered it later the output is
> incorrect.
> out2a=downsample(out1a,4);
> out2b=filter(h1,1,out2a);
> Any help is highly appreciated.
> Thanks,
> EngGan > _____________________________________
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Reply by egan_nc June 30, 20032003-06-30
Hi,
I designed a filter using remezord function. When I filtered the
input first and downsampled later, the filter works fine.
out2a=filter(h1,1,out1a);
out2b=downsample(out2a,4);
But when I downsampled first and then fitlered it later the output is
incorrect.
out2a=downsample(out1a,4);
out2b=filter(h1,1,out2a);
Any help is highly appreciated.
Thanks,
EngGan