# Line slope calculator 6x+y=8

**Straight line given by points A[0; 8] and B[1; 2]**

## Calculation:

**Slope-intercept form of line:**y = -6x+8

**Canonical form of the line equation:**6x+y-8 = 0

**Parametric form of the line equation:**

x = t

y = -6t+8 ; t ∈ R

**Slope:**m = -6

**Slope angle of line: φ =**-80°32'16″ = -1.4056 rad

**X intercept:**x

_{0}= 1.3333

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 1.3152

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(1; -6)

**Normal vector: n =**(6; 1)

**Midpoint of the segment AB: M =**[0.5; 5]

**Perpendicular Bisector equation:**x-6y+29.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (1; 2) ; |OB| = 2.2361**

**Scalar product OA .OB = 16**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**