johnbesel@web.de (Eugene) wrote:

>Hello, thank you for the answer,

Welcome.

>
>for the function iir32(DATA *x, LDATA *h, DATA *r ...)
>should be the length of 'h' 5*nbiq.
>
>If I think right, so if the length of Filter is 8, the should be the
>length of 'h' 4*5=20
>
>If I produce the coef. with Matlab, so I get the number of coefs 24. I
>can't devide this number with 5.
>
>What should I do? 
>
>Or It isn't the coefs. what I get with matlab. "Dig Proc Toolbox"?

I think is answered in the next reply ... that they are giving you the
coefficients for a0, a1, a2, b0, b1, and b2 ( i.e. 6 * 4 = 24 )... and
you need to divide through by the coefficient on y[n] to get only the
5 coefficients required by TI.

>
>best regard.
>Eugene

Same,

Robert



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Hello, thank you for the answer,

for the function iir32(DATA *x, LDATA *h, DATA *r ...)
should be the length of 'h' 5*nbiq.

If I think right, so if the length of Filter is 8, the should be the
length of 'h' 4*5=20

If I produce the coef. with Matlab, so I get the number of coefs 24. I
can't devide this number with 5.

What should I do? 

Or It isn't the coefs. what I get with matlab. "Dig Proc Toolbox"?

best regard.
Eugene