Reply by mdholmes June 28, 20052005-06-28
The problem lies in the Complex.h, as you indicated.  Apparently, I had a
local "Complex.h" that I was including (used company-wide) as opposed to
the widely accepted standard C-version, <complex.h>.  Thanks again for
your help.

-Mark

>If you #include <complex.h> (*not* <Complex.h>, whatever that is) >before fftw.h, *and* your compiler is C99-compliant (at least as far as >complex types go), then fftw_complex is the same thing as C99's "double >complex" type, as described in the manual. > >If you are using some non-C99 complex data type or your compiler is not >C99-compliant, then this will not work. However, if your complex data >type consists of the real part followed by the imaginary part (e.g. >struct { double real, imag; }) then it should be bit compatible with >fftw_complex and you can just typecast your array pointer when passing >to FFTW. > >Steven > >
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Reply by June 23, 20052005-06-23
If you #include <complex.h> (*not* <Complex.h>, whatever that is)
before fftw.h, *and* your compiler is C99-compliant (at least as far as
complex types go), then fftw_complex is the same thing as C99's "double
complex" type, as described in the manual.

If you are using some non-C99 complex data type or your compiler is not
C99-compliant, then this will not work.  However, if your complex data
type consists of the real part followed by the imaginary part (e.g.
struct { double real, imag; }) then it should be bit compatible with
fftw_complex and you can just typecast your array pointer when passing
to FFTW.

Steven

Reply by mdholmes June 22, 20052005-06-22
>Data[j][0] is the real part and Data[j][1] is the imaginary part; what >else is there to understand? Surely you can write a loop yourself? > >Regarding typecasts, it depends on what "complex" type you are talking >about. Conversion from both the C99 complex types and the C++ complex >types are described in the reference section of the FFTW manual. > >It sounds like you are having basic problems with the C language, and >comp.lang.c might be a more appropriate forum (or comp.lang.c++ if you >are using C++). > >Cordially, >Steven G. Johnson >
For the record, this is in C. Also, I completely understand the data type (e.g.-Data[j][0],Data[j][1]...) fftw_complex has. The manual makes it seem as if you don't *need* to put it in that type, however. As long as you put your #include <Complex.h> before the #include <fftw3.h>. A simple for loop is easy, yes. However, it is also inefficient. If the fftw supports "complex" data types, I would like to take advantage of not having to run a loop every time to cast it into fftw_complex data. However, if it is not supported, in fact, then I'll have to do it the old fashion way. I appreciate your help, Steven. Maybe my questions are too vague and/or you are receiving them wrong. I don't think the problem is a comfort level with the C language by any means. Regards, Mark This message was sent using the Comp.DSP web interface on www.DSPRelated.com
Reply by June 21, 20052005-06-21
mdholmes wrote:
> When I attempt to execute the plan with "complex" data, I get a compile > error. However, when I execute on "complex" data cast into "fftw_complex" > within the plan call, it compiles and runs. Unfortunately, it does not > cast the complex data into equivalent "fftw_complex" data. Do you have to > go term by term (for loop) and put the data in Data[j][0] for real and > Data[j][1] for imaginary manually? Or is there a way to either execute > the plan on "complex" data and/or effectively cast "complex" data to > "fftw_complex"? Thanks again.
Data[j][0] is the real part and Data[j][1] is the imaginary part; what else is there to understand? Surely you can write a loop yourself? Regarding typecasts, it depends on what "complex" type you are talking about. Conversion from both the C99 complex types and the C++ complex types are described in the reference section of the FFTW manual. It sounds like you are having basic problems with the C language, and comp.lang.c might be a more appropriate forum (or comp.lang.c++ if you are using C++). Cordially, Steven G. Johnson
Reply by mdholmes June 20, 20052005-06-20
I have the manual and have read the related chapters; however, there seems
to be some ambiguity in what values the variables should take on.  I
appreciate the help, though.  Using values reflected in your response did
not prove any better in running the planner.  I believe the problem is in
the casting of the data.

When I attempt to execute the plan with "complex" data, I get a compile
error.  However, when I execute on "complex" data cast into "fftw_complex"
within the plan call, it compiles and runs.  Unfortunately, it does not
cast the complex data into equivalent "fftw_complex" data.  Do you have to
go term by term (for loop) and put the data in Data[j][0] for real and
Data[j][1] for imaginary manually?  Or is there a way to either execute
the plan on "complex" data and/or effectively cast "complex" data to
"fftw_complex"?  Thanks again.

-Mark

>n[0] = N >howmany=M >idist=N >istride=1 >inembed = onembed = NULL > >Assuming you use the same layout for the output, odist=idist and >ostride=istride. > >Cordially, >Steven G. Johnson > >PS. You know, all of these parameters *are* documented in the manual. > >
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Reply by June 16, 20052005-06-16
mdholmes wrote:
> I am using FFTW 3.0.1 with a C-program I'm developing. My input data > consists of a block of complex data for M channels ordered in the > following fashion: > > input = [ chan1_sample0, chan1_sample1,...,chan1_sampleN-1, > chan2_sample0,...,chan2_sampleN-1,...,...,chanM_sample0,...,chanM_sampleN-1] > > I would like to take advantage of the "Advanced Complex DFT" capability > (e.g.-fftw_plan_many_dft()) to avoid having to call the routine for every > FFT-size for each channel. If I wanted to take an LF-size fft of the > input for each channel, how do I set my arguments accordingly given the > abovementioned input layout? In particular, I am confused what to make my > "const int *n", "int howmany", "const int *{i,o}nembed", "{i,o}stride", > "{i,o}dist", etc. Thanks in advance.
n[0] = N howmany=M idist=N istride=1 inembed = onembed = NULL Assuming you use the same layout for the output, odist=idist and ostride=istride. Cordially, Steven G. Johnson PS. You know, all of these parameters *are* documented in the manual.
Reply by mdholmes June 16, 20052005-06-16
I am using FFTW 3.0.1 with a C-program I'm developing.  My input data
consists of a block of complex data for M channels ordered in the
following fashion:

input = [ chan1_sample0, chan1_sample1,...,chan1_sampleN-1,
chan2_sample0,...,chan2_sampleN-1,...,...,chanM_sample0,...,chanM_sampleN-1]

I would like to take advantage of the "Advanced Complex DFT" capability
(e.g.-fftw_plan_many_dft()) to avoid having to call the routine for every
FFT-size for each channel.  If I wanted to take an LF-size fft of the
input for each channel, how do I set my arguments accordingly given the
abovementioned input layout?  In particular, I am confused what to make my
"const int *n", "int howmany", "const int *{i,o}nembed", "{i,o}stride",
"{i,o}dist", etc.  Thanks in advance.

Regards,

Mark


		
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