Reply by December 20, 20052005-12-20
Jerry Avins wrote:
> allanherriman@hotmail.com wrote: > > Richard Owlett wrote: > > > >>ashcroft2006 wrote: > > > > > >>I don't really wish to "rain on your parade" > >>*BUT* > >>Is your interference *ONLY* at 20 Hz? > >>Could it also be at harmonics of 20 Hz? > > > > > > I was guessing that it was the third harmonic of 60Hz mains, aliased > > down to 20Hz by the 200Hz sampler. > > > > If that's the case, it could be possible to reduce the level of the > > 20Hz interference by cancelling it (e.g. by sampling the mains, > > estimating the 20Hz component, then subtracting it from the ECG > > signal), rather than by filtering it out. > > > > It might also be possible to fix this with a 180 Hz notch or low pass > > filter prior to sampling at 200Hz. > > > > Or you could sample at some higher frequency, and eliminate the 180Hz > > with a simple low pass filter. > > > > These solutions give lower distortion of the wanted signal than a > > simple 20Hz notch filter. > > Allan, > > If it is as you guess, I'd call it a failure of the anti-alias filter. I > don't see how cancellation would work if the sample clock and power line > weren't derived from the same master, and even so, the phase would > likely depend on the lead placement. > > An important issue is whether the signals are already acquired, or if > the acquisition can be made cleaner.
This wasn't apparent from the OP's post :(
> It does no good to filter the input from the leads if there is > hum on the power supply.
PSU ripple on a supply rail would give even harmonics, and magnetic leakage from the transformer would be mostly fundamental (I think), so I assumed that the third was being picked up through capacitive coupling from the mains to the body under test. Proper probing could help here. Too many guesses, and not enough information from the OP! I'll stop now. Regards, Allan
Reply by Jerry Avins December 20, 20052005-12-20
allanherriman@hotmail.com wrote:
> Richard Owlett wrote: > >>ashcroft2006 wrote: > > >>I don't really wish to "rain on your parade" >>*BUT* >>Is your interference *ONLY* at 20 Hz? >>Could it also be at harmonics of 20 Hz? > > > I was guessing that it was the third harmonic of 60Hz mains, aliased > down to 20Hz by the 200Hz sampler. > > If that's the case, it could be possible to reduce the level of the > 20Hz interference by cancelling it (e.g. by sampling the mains, > estimating the 20Hz component, then subtracting it from the ECG > signal), rather than by filtering it out. > > It might also be possible to fix this with a 180 Hz notch or low pass > filter prior to sampling at 200Hz. > > Or you could sample at some higher frequency, and eliminate the 180Hz > with a simple low pass filter. > > These solutions give lower distortion of the wanted signal than a > simple 20Hz notch filter.
Allan, If it is as you guess, I'd call it a failure of the anti-alias filter. I don't see how cancellation would work if the sample clock and power line weren't derived from the same master, and even so, the phase would likely depend on the lead placement. An important issue is whether the signals are already acquired, or if the acquisition can be made cleaner. It does no good to filter the input from the leads if there is hum on the power supply. Jerry -- Engineering is the art of making what you want from things you can get. �����������������������������������������������������������������������
Reply by December 20, 20052005-12-20
Richard Owlett wrote:
> ashcroft2006 wrote:
> I don't really wish to "rain on your parade" > *BUT* > Is your interference *ONLY* at 20 Hz? > Could it also be at harmonics of 20 Hz?
I was guessing that it was the third harmonic of 60Hz mains, aliased down to 20Hz by the 200Hz sampler. If that's the case, it could be possible to reduce the level of the 20Hz interference by cancelling it (e.g. by sampling the mains, estimating the 20Hz component, then subtracting it from the ECG signal), rather than by filtering it out. It might also be possible to fix this with a 180 Hz notch or low pass filter prior to sampling at 200Hz. Or you could sample at some higher frequency, and eliminate the 180Hz with a simple low pass filter. These solutions give lower distortion of the wanted signal than a simple 20Hz notch filter. Regards, Allan
Reply by Jack Ace December 20, 20052005-12-20
ashcroft2006 wrote:

> Hey > Im a student and need help using matlab. im extremeley new to signal > processing so this is a pretty basic question, im hoping someone can help > me. > > im removing noise from an ecg signal and i need to remove this noise at > 20hz using a notch filter, sampling rate is 200hz. the matlab code is: > > >>>a=[x x x] > >>>b=[x x x] > >>>zfiltered=filter(a,d,z) > > 'z' is my noise corrupted signal, but how do i work out the coeffs needed > for 'a' and 'b'? > sorry for the "newbie" question but im in desperte need of help. > > Any help is much appreciated, > Mark
%%%%%%%%%%%%%%%%%%%%% Notch Filter Fs = 200; % sampling freq [Hz] Fn = Fs/2; % Nyquist freq [Hz] W0 = 20; % notch frequency [Hz] w0 = W0*pi/Fn; % notch frequency normalized BandWidth = 5; % -3dB BandWidth [Hz] B = BandWidth*pi/Fn; % normalized bandwidth k1 = -cos(w0); k2 = (1 - tan(B/2))/(1 + tan(B/2)); b = [1+k2 2*k1*(1+k2) 1+k2]; a = [2 2*k1*(1+k2) 2*k2]; figure(1); % look at the frequency response of your filter freqz(b,a); title('sampling frequency 200Hz, notch @ 20HzHz, notch bandwidth 5Hz'); % z : your signal zfiltered=filter(b,a,z); % use different bandwidth for having different transient responses % narrowing the bandwidth-> increasing transient duration % if you want to check it, filter a unit step signal. %%%%%%%%%%%%%%%%%%%%%%%%%% Hope this could help Bye Jack
Reply by Richard Owlett December 19, 20052005-12-19
ashcroft2006 wrote:

> Hey > Im a student and need help using matlab. im extremeley new to signal > processing so this is a pretty basic question, im hoping someone can help > me. > > im removing noise from an ecg signal and i need to remove this noise at > 20hz using a notch filter, sampling rate is 200hz. the matlab code is: > > >>>>a=[x x x] >>>>b=[x x x] >>>>zfiltered=filter(a,d,z) > > > 'z' is my noise corrupted signal, but how do i work out the coeffs needed > for 'a' and 'b'? > sorry for the "newbie" question but im in desperte need of help. > > Any help is much appreciated, > Mark > >
I don't really wish to "rain on your parade" *BUT* Is your interference *ONLY* at 20 Hz? Could it also be at harmonics of 20 Hz? I assume that by "ecg" you mean "electrocardiogram" aka EKG. More than 40 years ago, as a student tech, I was involved in recording Electroencephalograph (EEG) traces of individual neurons. Back then I did not understand "common mode" vs "normal mode" interference. The EE's on this forum can appreciate just how far I got trying to "filter" the noise :{ I said all this to say -- give more info ;)
Reply by john December 19, 20052005-12-19
ashcroft2006 wrote:
> Hey > Im a student and need help using matlab. im extremeley new to signal > processing so this is a pretty basic question, im hoping someone can help > me. > > im removing noise from an ecg signal and i need to remove this noise at > 20hz using a notch filter, sampling rate is 200hz. the matlab code is: > > >>>a=[x x x] > >>>b=[x x x] > >>>zfiltered=filter(a,d,z) > > 'z' is my noise corrupted signal, but how do i work out the coeffs needed > for 'a' and 'b'? > sorry for the "newbie" question but im in desperte need of help. > > Any help is much appreciated, > Mark
Here is some sample code that you can modify: Fs = 8000; Fn = 1000; r = 0.99; wz = 2*pi*Fn/Fs; c = cos(wz); bnotch=[1, -2*c, 1]; anotch=[1, -2*r*c, r*r]; y = filter(bnotch, anotch, x);
Reply by Bhaskar Thiagarajan December 19, 20052005-12-19
"ashcroft2006" <mark_ashcroft@hotmail.com> wrote in message
news:zdWdnaXfZfAweTveRVn-iA@giganews.com...
> Hey > Im a student and need help using matlab. im extremeley new to signal > processing so this is a pretty basic question, im hoping someone can help > me. > > im removing noise from an ecg signal and i need to remove this noise at > 20hz using a notch filter, sampling rate is 200hz. the matlab code is: > > >>>a=[x x x] > >>>b=[x x x] > >>>zfiltered=filter(a,d,z) > > 'z' is my noise corrupted signal, but how do i work out the coeffs needed > for 'a' and 'b'? > sorry for the "newbie" question but im in desperte need of help.
Well...since you have matlab, there are several tools (from beginner to advanced) to help you. You can either use 'fdatool' or 'sptool' - both give you fairly simple interfaces to design filters. I suggest you start with an FIR filter (this will make one set of your coeffs = 1, so you'd use filter(b,1,z) when you invoke the matlab command). The help files for either filter design program will give you plenty of info on how to set various parameters. Also, you need to know how good your notch filter needs to be at 20 Hz. If you don't know how good, then you have more reading to do (ask your professor or TA). Cheers Bhaskar
Reply by John Herman December 19, 20052005-12-19
If this is a time limited chunk of data and the results are not required in 
real time, you might convert the signal to the frequency domain using the 
discrete Fourier transform (DFT), windowing the frequency domain data to 
eliminate the offending noise, and then performing the inverse discrete 
Fourier transform.  This is as easy as it gets and works in Matlab.

If you have to do this in real time, junk Matlab.  If you have to use Matlab 
for some reason, investigate the remez function and FIR filters for your data.

In article <zdWdnaXfZfAweTveRVn-iA@giganews.com>, "ashcroft2006" 
<mark_ashcroft@hotmail.com> wrote:
>Hey >Im a student and need help using matlab. im extremeley new to signal >processing so this is a pretty basic question, im hoping someone can help >me. > >im removing noise from an ecg signal and i need to remove this noise at >20hz using a notch filter, sampling rate is 200hz. the matlab code is: > >>>>a=[x x x] >>>>b=[x x x] >>>>zfiltered=filter(a,d,z) > >'z' is my noise corrupted signal, but how do i work out the coeffs needed >for 'a' and 'b'? >sorry for the "newbie" question but im in desperte need of help. > >Any help is much appreciated, >Mark > >
Reply by ashcroft2006 December 19, 20052005-12-19
Hey
Im a student and need help using matlab. im extremeley new to signal
processing so this is a pretty basic question, im hoping someone can help
me.

im removing noise from an ecg signal and i need to remove this noise at
20hz using a notch filter, sampling rate is 200hz.  the matlab code is:

>>>a=[x x x] >>>b=[x x x] >>>zfiltered=filter(a,d,z)
'z' is my noise corrupted signal, but how do i work out the coeffs needed for 'a' and 'b'? sorry for the "newbie" question but im in desperte need of help. Any help is much appreciated, Mark