> By the way, why are there also so many answers although they are not
> real answers to the requested question? It is very interesting to me
> that somebody not just ignores it but posts something to the question.
> Is it because we already become familiar with that question as we are
> familiar with Gooooooogle.
Frustration at the same question being asked repeatedly by someone who
seemingly doesn't know what it means.
Jerry
--
Engineering is the art of making what you want from things you can get.
�����������������������������������������������������������������������
Reply by James G.●January 14, 20062006-01-14
By the way, why are there also so many answers although they are not
real answers to the requested question? It is very interesting to me
that somebody not just ignores it but posts something to the question.
Is it because we already become familiar with that question as we are
familiar with Gooooooogle.
- James Gold
Reply by Mark●January 13, 20062006-01-13
the magic number is -1.6 dB
Mark
Reply by Thomas Magma●January 13, 20062006-01-13
"Jerry Avins" <jya@ieee.org> wrote in message
news:cPmdnfxwO94DRVrenZ2dnUVZ_tydnZ2d@rcn.net...
> omg wrote:
>> base on the shannon capacity limit,dicuss the possibility of transmitting
>> information when siganl is lower than the noise?
>>
>> some ways of trasmitting would be be spreading the specturm,using reed
>> coding method.
>>
>> what are some other ways to transmit information when signal is lower
>> than the noise
>
> What, again? Does your prof keep asking the same question or are you stuck
> in a time loop?
>
> Jerry
> --
> Engineering is the art of making what you want from things you can get.
> �����������������������������������������������������������������������
I should have said...The frequency in which you asked this question can be
filtered by averaging the background noise of unique questions. You should
see some spectral gain at around 1.751 E-6 Hz.
Thomas
Reply by Jerry Avins●January 13, 20062006-01-13
omg wrote:
> base on the shannon capacity limit,dicuss the possibility of transmitting
> information when siganl is lower than the noise?
>
> some ways of trasmitting would be be spreading the specturm,using reed
> coding method.
>
> what are some other ways to transmit information when signal is lower
> than the noise
What, again? Does your prof keep asking the same question or are you
stuck in a time loop?
Jerry
--
Engineering is the art of making what you want from things you can get.
�����������������������������������������������������������������������
Reply by Thomas Magma●January 12, 20062006-01-12
You can average out the noise to reveal a signal. Your averaging window size
has to be less that or equal to the bit rate or you will start to average
out the information.
Thomas
"omg" <jimmybai123@yahoo.com> wrote in message
news:csmdnczuxoEBb1veRVn-tQ@giganews.com...
>
> base on the shannon capacity limit,dicuss the possibility of transmitting
> information when siganl is lower than the noise?
>
> some ways of trasmitting would be be spreading the specturm,using reed
> coding method.
>
> what are some other ways to transmit information when signal is lower
> than
> the noise
>
>
Reply by omg●January 12, 20062006-01-12
base on the shannon capacity limit,dicuss the possibility of transmitting
information when siganl is lower than the noise?
some ways of trasmitting would be be spreading the specturm,using reed
coding method.
what are some other ways to transmit information when signal is lower
than
the noise