Reply by Clay S. Turner●February 18, 20062006-02-18
"LPG1976" <gill@gel.ulaval.ca> wrote in message
news:wcidna3g0rcvrGzeRVn-oA@giganews.com...
> Hi,
>
> I have to find a new radar receiver design to increase the SNR. The signal
> bandwidth is 2 MHz (a CW Phase modulated signal). With a common receiver
> design (receiver BW at 2 MHz too), the SNR is too low for detection. To
> increase the SNR, I can reduce the noise power in my receiver by reducing
> the receiver bandwidth. Can someone tell me if it's possible to do that
> and how (filter bank maybe?).
>
As someone else asked, is your noise thermal or from something else? If
thermal, then you may chill the detector and 1st LNA. What is your current
noise figure?
Cly
Reply by Mike Yarwood●February 15, 20062006-02-15
"LPG1976" <gill@gel.ulaval.ca> wrote in message
news:m6ydnW-xc-I2Cm7eRVn-iA@giganews.com...
> >ggroupsthomas@gmail.com wrote:
>>>>you can also use multiple pulses, see Whalen's Detection Theory book
>>>
>>>
>>> not in this case, as the OP states it is a CW (continuous wave) radar.
>>>
>>Indeed he did. multiple CW?
>>
>
> To going deeper in details, the signal is a QPSK modulated signal of 2 MHz
> bandwidth. I have to deal with it (PCL...). So, the SNR of the echo (a
> target) have to be increased (i.e.: the noise power decreased).
>
If it's passive, and you have no control of the illuminating source(s) then
you could simply increase the number of receivers ( and receive antennas) or
bands that you process (if there are other strong transmissions illuminating
your target volume). Almost certainly best to see if you can cheaply
improve the receiver noise figure , increase your integration/ correlation
time, or optimise your antenna pattern and meet specs first ( as others have
already suggested in much more detail).
Are you sure it's noise and not interference that is causing your problem ?
If so - what type of noise?
Best of Luck - Mike
Reply by LPG1976●February 15, 20062006-02-15
>ggroupsthomas@gmail.com wrote:
>>>you can also use multiple pulses, see Whalen's Detection Theory book
>>
>>
>> not in this case, as the OP states it is a CW (continuous wave) radar.
>>
>Indeed he did. multiple CW?
>
To going deeper in details, the signal is a QPSK modulated signal of 2 MHz
bandwidth. I have to deal with it (PCL...). So, the SNR of the echo (a
target) have to be increased (i.e.: the noise power decreased).
Thank you very much
Reply by Stan Pawlukiewicz●February 15, 20062006-02-15
ggroupsthomas@gmail.com wrote:
>>you can also use multiple pulses, see Whalen's Detection Theory book
>
>
> not in this case, as the OP states it is a CW (continuous wave) radar.
>
Indeed he did. multiple CW?
Reply by ●February 15, 20062006-02-15
>>> you can also use multiple pulses, see Whalen's Detection Theory book
>> not in this case, as the OP states it is a CW (continuous wave) radar.
>Phase modulated
I don't see that it being phase modulated makes the slightest bit of
difference. The phase modulation simply means the signal has
non-negligible bandwidth, so the receiver bandwidth must be adequate to
receive it (and hence its total thermal noise is higher). The radar
will have range resolution as a result of this bandwidth. If there
were no modulation, the receiver bandwidth could be reduced to only
that of the expected doppler shift.
Either way, the signal is continuous, so signal and noise *powers* can
be inserted in the "radar equation". The OP may wish to integrate the
matched filter or doppler filter bank outputs for as long as he wishes
in order to increase the SNR of the signal used for detection
decisions, but there are no "pulses" (by definition amplitude
modulated) to contend with.
I suppose you might consider a phase modulated code repetition to be a
"pulse", but that would be rather unconventional as the duty cycle is
1! In the pulsed case, the radar equation "expects" unmodulated pulses
with bandwidth = 1/pulse_length if you simply stick the numbers in
without thinking, so if pulse compression is used (so the actual duty
cycle is higher) then you must factor this in.
But in this CW case, phase modulated or not, the transmitter output
power is essentially constant, so there are no more degrees of freedom
re the SNR *at the receiver*.
The SNR at the *detector* depends in this case simply on the
integration time, which might be chosen depending on the detector
update rate required, as well as the standard SNR-based criteria (prob
of false alarm, detection, etc) ...
The radar equation looks (and is) pretty simple, but it is possible to
make gross miscalculations without verifying the way that is was
derived and how that corresponds to a particular system, and without
considering the difference between SNR at the receiver (eg at RF or IF)
and at the detector. It's possible this is the cause of the OP's
problem in calculation (or else a very low tx power, very high range,
or an unusual detection statistic is required).
Reply by Mike Yarwood●February 15, 20062006-02-15
<ggroupsthomas@gmail.com> wrote in message
news:1139966530.535939.126650@o13g2000cwo.googlegroups.com...
>> you can also use multiple pulses, see Whalen's Detection Theory book
>
> not in this case, as the OP states it is a CW (continuous wave) radar.
>
Phase modulated
best of luck - Mike
Reply by ●February 14, 20062006-02-14
> you can also use multiple pulses, see Whalen's Detection Theory book
not in this case, as the OP states it is a CW (continuous wave) radar.
Reply by Stan Pawlukiewicz●February 14, 20062006-02-14
ggroupsthomas@gmail.com wrote:
> This is a radar so there's no data to transmit as such.
>
> You can reduce the bandwidth but that will reduce the range resolution
> (assuming that is important).
>
> You can increase SNR in the ways Randy describes, or by *coherently*
> integrating the received signal for longer. But if you have CW
> operation and your power budget already has you continuously
> integrating the *output of a matched filter*, then there's not much you
> can do in terms of DSP or filter architectures - you need more power
> one way or another (transmitter power amps, antenna directionality) or
> a lower noise receiver.
>
> Are you sure your calculations are correct, ie you are measuring the
> matched filter output SNR?
>
you can also use multiple pulses, see Whalen's Detection Theory book.
Reply by ●February 14, 20062006-02-14
This is a radar so there's no data to transmit as such.
You can reduce the bandwidth but that will reduce the range resolution
(assuming that is important).
You can increase SNR in the ways Randy describes, or by *coherently*
integrating the received signal for longer. But if you have CW
operation and your power budget already has you continuously
integrating the *output of a matched filter*, then there's not much you
can do in terms of DSP or filter architectures - you need more power
one way or another (transmitter power amps, antenna directionality) or
a lower noise receiver.
Are you sure your calculations are correct, ie you are measuring the
matched filter output SNR?
Reply by Randy Yates●February 13, 20062006-02-13
"Mark" <makolber@yahoo.com> writes:
> [...]
> You can lower the noise figure of the front end so there is less noise
> in the receiver to start with...
Or you can increase the gain of the receive antenna...
Or the output power of the transmitter...
Or the gain of the transmit antenna...
--
% Randy Yates % "Maybe one day I'll feel her cold embrace,
%% Fuquay-Varina, NC % and kiss her interface,
%%% 919-577-9882 % til then, I'll leave her alone."
%%%% <yates@ieee.org> % 'Yours Truly, 2095', *Time*, ELO
http://home.earthlink.net/~yatescr