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`f(t)=20-28/55t``f(t)=(20-55t)/28``f(t)=(20-28t)/55``f(t)=20-(55t)/28`

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DTranscript

Time | Transcript |
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00:00 - 00:59 | the gas mileage for Jankari 28 miles per gallon when the car travels a certain average speed of 55 mph the car that has 20 gallons of tank at the beginning of a trip is Jain write an average speed of 45 which of the following function at model the number of gallons of gas remaining in the tank t h after the critical so basically it says that there are 20 gallons at the start of the trip to 20 ever constant OK then it says that the guy drives at an average speed of 55 mph ok so let us say driving at 55 miles sorry 55 mph show in PVR he will drive 55 into Ti distance of 55 into 3 miles |

01:00 - 01:59 | now we have to see how to calculate the number of gallons which are present after a particular time so he says that 25 miles per gallon are used because the gas mileage is 2520 28 miles per gallon are used to cause the gas Mai the mileage of the car is 28 miles per gallon to basically for 28 miles 1 gallon is used simple unitary method using for 28 miles 1 gallon is used for 1 mile one upon 28 gallons will be used simple and spoon now I understand that 45550 MI because he had travelled in tea time 55 55 |

02:00 - 02:59 | upon 28 gallons will be used this amount of Gal will be used if so the amount of Gal that we are left with will be 20 - 55 Ti bi 28 because this is used up this was at the starting the remaining with this much amount of Gal this becomes our answer so option De Vich perfectly matches this becomes our answer thank you |

**Introduction**

**Equation: a statement of equality which contains one or more unknown quality or variable ( literals) is called an equation**

**Linear Equation: an equation involving only linear polynomials is called a linear equation**

**Solution: a value of the variable which when substituted for the variable in on equation makes` L.H.S. =R.H.S.`is said to satisfy the equation and is called a solution or a root of the equation .**

**Solving an equation: solving an equation means determining its roots**

**Solving equations having variable terms on one side and number(s) on the other side**

**Transposition method**

**Solve : `(3t-2)/4 - (2t+3)/3 = 2/3 - t`**

**Solve : `2/5x -5/3x =1/15 `**

**Cross-multiplication method for solving equations of the form `(ax+b)/(cx+d) = m/n`**