Reply by arkkimede May 6, 20092009-05-06
Sorry yesterday I was confuse and the solution proposed in unfeasible.

On Tue, May 5, 2009 at 2:45 PM, arkkimede wrote:
> If M is a little number you can generate the first sequence evaluate
> is energy and impose that this is M.
>
> Then you can obtain the other sequence solving a linear system (rectangular) .
> But what I do not know if the other sequence have energy equal to M.
>
> E.G.
> Suppose M=5
>
> Generate 1^ sequence [A1 A2 A3 A4 A5]
>
> Then
> A1
> B1 B2 B3 B4 B5 A2 -1
> C1 C2 C3 C4 C5 x A3 = -1
> D1 D2 D3 D4 D5 A4 -1
> E1 E2 E3 E4 E5 A5 -1
>
> To solve it use svd.
> On 5/1/09, m...@yahoo.com wrote:
>> Can any body give me some reference how to generate PN sequence with
>> required autocorrelation characteristics.If Pi is the sequence of length M
>> PiPj = M if i =j
>> PiPj = -1 else
>> Thank you
>> Rakesh
>
Reply by arkkimede May 6, 20092009-05-06
If M is a little number you can generate the first sequence evaluate
is energy and impose that this is M.

Then you can obtain the other sequence solving a linear system (rectangular) .
But what I do not know if the other sequence have energy equal to M.

E.G.
Suppose M=5

Generate 1^ sequence [A1 A2 A3 A4 A5]

Then
A1
B1 B2 B3 B4 B5 A2 -1
C1 C2 C3 C4 C5 x A3 = -1
D1 D2 D3 D4 D5 A4 -1
E1 E2 E3 E4 E5 A5 -1

To solve it use svd.

On 5/1/09, m...@yahoo.com wrote:
> Can any body give me some reference how to generate PN sequence with
> required autocorrelation characteristics.If Pi is the sequence of length M
> PiPj = M if i =j
> PiPj = -1 else
> Thank you
> Rakesh
>
Reply by muna...@yahoo.com May 5, 20092009-05-05
Can any body give me some reference how to generate PN sequence with required autocorrelation characteristics.If Pi is the sequence of length M
PiPj = M if i =j
PiPj = -1 else
Thank you
Rakesh