Reply by BERT June 20, 20072007-06-20
On Jun 20, 10:59 am, VijaKhara <VijaKh...@gmail.com> wrote:
> Hi all > > I am reading the Papoulis's book on Random Variable and getting > confused with the following formula: > > X(t) is input of a linear system with impulse response h(t), Y(t) is > its output. > X(t) is a WSS Random Process > ===> the Cross Correlation: Rxy(to)= Rxx(to) * h*(-to). where * is > convolution, and h*(-to) is conjugate of h(-to). > > Now the density spectrum Sxy(omega)= Sxx(omega)H*(omega). > > I am confused, I think it should be Sxy(omega)= Sxx(omega)H*(-omega)., > because the CTFT of x(-t) is X(-omega). > > AM I missing some point> > > Thanks
If your input signal is real-valued, then the Fourier transform is symmetric, and hence H(w) = H(-w). If your input signal is complex valued, then the transformation H'(w) = H(-w) is called spectral inversion => the real and imaginary parts of x(t) are interchanged in the time-domain. Regards, BERT.
Reply by VijaKhara June 20, 20072007-06-20
Hi all

I am reading the Papoulis's book on Random Variable and getting
confused with the following formula:

X(t) is input of a linear system with impulse response h(t), Y(t) is
its output.
X(t) is a WSS Random Process
===> the Cross Correlation:  Rxy(to)= Rxx(to) * h*(-to).  where * is
convolution, and h*(-to) is conjugate of h(-to).

Now the density spectrum Sxy(omega)= Sxx(omega)H*(omega).

I am confused, I think it should be Sxy(omega)= Sxx(omega)H*(-omega).,
because the CTFT of x(-t) is X(-omega).

AM I missing some point>

Thanks