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yaar, there is no mathematical relationship b/w the fourier of a funtion
and fourier of absolute of the function See the fact that square root and absolute both are not realizable.[ see graph of sqrt(x(t)) and abs(x(t)) against t ]... or u can say that absolute of x(t) is irreversible. We loose information that we cannot get again, so the abs(x(t)) becomes entirly new function that has no relationship with the prev function ----- Original Message ----- From: Arnaldo Batista To: Sent: Sunday, March 17, 2002 12:08 AM Subject: [matlab] FT of abs(f) Helo there, Is there a mathematical relationship between the Fourier Transform of a function and the Fourier Transform of the absolute value of the same function. I tried to use the fact that abs(f)=sqrt(f^2), but could not reach a lean mathematical relation...note that f is a function with positive and negative values. AB _____________________________________ Note: If you do a simple "reply" with your email client, only the author of this message will receive your answer. You need to do a "reply all" if you want your answer to be distributed to the entire group. _____________________________________ About this discussion group: To Join: To Post: To Leave: Archives: http://www.yahoogroups.com/group/matlab More DSP-Related Groups: http://www.dsprelated.com/groups.php3 |