Let's assume there is a certain periodic sequence m (t). Further from it
calculated s(t)=[m(t)+j*hilbert(m(t))]*exp(j*2*pi*f*t).

Then it is calculated it ACF 
 r(m)=(1/(Ncorr-m))*sum(от n=0 до Ncorr-1-m){conj(Vj)*Vj(n+m)}.

Further in the module of this ACF the maximal peak is searched, we shall
assume with number Mmax.

Let's designate frequency of sampling as Fs. 
If I correctly understand Fs/Mmax will give me the basic frequency of
sequence m(t).

And what means (arg [r(Mmax)] / (2pi)) * (Fs/Mmax)?