Math Forumla giving 165 bits per sample?

http://www.ee.washington.edu/conselec/A95/projects/surround/surround.html

"As a reference, compact discs (CDs) have a dynamic range of 96 dB
using 16-bit Pulse Code Modulation (PCM), and a resolution of 165 bits
per audio sample operating at a sampling rate of 44.1 kHz. This is
705,600 bits of data per second per channel. The CD can store up to 74
minutes of two channel music on a single disc."

What equation do I use gets the number of bits per sample?

How did that website get 165 bits per audio sample?

Isn't CD audio 16 bits/sample? 

44100 [16] = 705600

CD is stereo, so 705600 [2] = 1411200 

2^16 = 65536 different levels of loudness

16-bit = 16[6] = 96 dB dynamic range

I am still confused about the 165 bit per audio sample. Is it a typo?

Just a typo.  165 should be 16.  Probably slipped off the 6 and hit the 5.

"Curious" <curious11112001@yahoo.com> wrote in message
news:34a4f456.0403161543.48a25f28@posting.google.com...
> http://www.ee.washington.edu/conselec/A95/projects/surround/surround.html
>
> "As a reference, compact discs (CDs) have a dynamic range of 96 dB
> using 16-bit Pulse Code Modulation (PCM), and a resolution of 165 bits
> per audio sample operating at a sampling rate of 44.1 kHz. This is
> 705,600 bits of data per second per channel. The CD can store up to 74
> minutes of two channel music on a single disc."
>
> What equation do I use gets the number of bits per sample?
>
> How did that website get 165 bits per audio sample?
>
> Isn't CD audio 16 bits/sample?
>
> 44100 [16] = 705600
>
> CD is stereo, so 705600 [2] = 1411200
>
> 2^16 = 65536 different levels of loudness
>
> 16-bit = 16[6] = 96 dB dynamic range
>
> I am still confused about the 165 bit per audio sample. Is it a typo?

On 16 Mar 2004 15:43:38 -0800, Curious wrote:

> 16-bit = 16[6] = 96 dB dynamic range
 
96dB = 20*log(2^16)

> I am still confused about the 165 bit per audio sample. Is it a typo?

No, but the first 149 bits are zero. ;-)

-- Mike --

Mike wrote:

> On 16 Mar 2004 15:43:38 -0800, Curious wrote:
> 
> 
>>16-bit = 16[6] = 96 dB dynamic range
> 
>  
> 96dB = 20*log(2^16)
> 
> 
>>I am still confused about the 165 bit per audio sample. Is it a typo?
> 
> 
> No, but the first 149 bits are zero. ;-)
> 

But wouldn't that introduce a significant DC offset ? ;-)

Paul