I have a question on the power of SSB (Single side band) AM. if transmitted signal is expressed as: u(t)=Ac*m(t)*cos(2pi*fc*t) plus minus Ac*H[m(t)]*sin(2*pi*fc*t), Ac=carrier amplitude, fc=carrier frequency, m(t)=message signal, and H[m(t)] is Hilbert transform of m(t). What is the equation for received power (Pr) in terms of power of message signal (Pm)? Some books say Pr=[(Ac^2)*Pm]/4, but other books say Pr=(Ac^2)*Pm. Which is right?? Thanks for the help. This problem is really killing me. =)

# Hilbert transform and SSB power??

Started by ●November 3, 2004

Reply by ●November 3, 20042004-11-03

Bob wrote:> I have a question on the power of SSB (Single side band) AM. > > if transmitted signal is expressed as: > > u(t)=Ac*m(t)*cos(2pi*fc*t) plus minus Ac*H[m(t)]*sin(2*pi*fc*t), > > Ac=carrier amplitude, fc=carrier frequency, m(t)=message signal, and > H[m(t)] is Hilbert transform of m(t). What is the equation for > received power (Pr) in terms of power of message signal (Pm)? > > Some books say Pr=[(Ac^2)*Pm]/4, but other books say Pr=(Ac^2)*Pm. > Which is right?? > > Thanks for the help. This problem is really killing me. =)Do the math for m(t) = 1, keeping in mind that H[m(t)] = 0. Then you'll know. -- Tim Wescott Wescott Design Services http://www.wescottdesign.com