Transforms

Started by manishp ●December 8, 2012

Reply by dvsarwate ●December 15, 20122012-12-15

On Tuesday, December 11, 2012 9:00:26 AM UTC-6, cl...@claysturner.com wrote:

> 
> 
> Recall ln(x) = integral[0,infinity]  (1/x) dx. 
> 

Please, Clay, the right side of your equation
does not depend on x at all (if the integral
even exists), and is very definitely NOT the
natural logarithm of x.

Dilip Sarwate

Reply by ●December 16, 20122012-12-16

On Saturday, December 15, 2012 7:21:55 AM UTC-5, dvsarwate wrote:
> On Tuesday, December 11, 2012 9:00:26 AM UTC-6, cl...@claysturner.com wrote:
> 
> 
> 
> > 
> 
> > 
> 
> > Recall ln(x) = integral[0,infinity]  (1/x) dx. 
> 
> > 
> 
> 
> 
> 
> 
> Please, Clay, the right side of your equation
> 
> does not depend on x at all (if the integral
> 
> even exists), and is very definitely NOT the
> 
> natural logarithm of x.
> 
> 
> 
> Dilip Sarwate

Sorry in my hast, I made an error. (pretty bad one)


ln(x) = integral(1,x) dy/y


Thanks Dilip,

Clay