Sirs, Generally, when fft is imimplemented in hw, due to prohibitive silicon area, the intermediate stages are allowed only 2 bit (for eg) growth. If I simply see this from a mathematical perspective, we do lose a very significant amount of bits due to this. How come this is acceptable and widely used in many hw fft implementation s? Thanks, manish
FFT in hw
Started by ●June 16, 2013