Here's a mind-challenge with no solution as far as I know. Maybe someone he= re will have an idea.=20 Let's say I have a continuous discrete-time signal that is 5 seconds long w= ith the Dirac impulses occurring once per second starting at 0. Now lets sa= y that I multiply this signal by a rectangular pulse that starts at t=3D1/2= and ends at t=3D4.5, so the first and last sample are 0. There are 2 ways = to compute the continuous Fourier transform of this , one is just to make a= new time signal with first and last sample=3D0 and take the FT, and the ot= her is to convolve the original spectrum (including the first and last impu= lses ) with the FT of the pulse (which will be a Sinc function with some ph= ase delay). The second method is where things get weird, because in the tim= e domain the pulse can start anywhere between 0+ epsilon and 1-epsilon, an= d end anywhere between 4+epsilon and 5-epsilon, and the time domain wavefor= m will be the same (0 for the 1st and last impulse ), so obviously the FT r= esult will be identical, but if you force yourself to use the frequency-dom= ain convolution method, the width of the sinc signal will vary continually = as you change the pulse width, and yet somehow you must get an identical co= nvolution result for that entire range of sinc widths (since the time domai= n signal doesn't change).=20 Can anyone explain this without resorting to the time domain ? Bob

# Theory for convolution

Started by ●July 17, 2017

Posted by ●July 17, 2017

On Monday, July 17, 2017 at 7:03:47 AM UTC-7, radam...@gmail.com wrote: ...> Let's say I have a continuous discrete-time signal ... > BobLet's not. You either have continuous time signals or discrete time signals. Convolution theorems are defined for each case, not for crossed cases. You also don't get to assign a 'length' to a signal without accounting for the windowing that requires. And, a discrete signal of length 5 with an initial sample at time 0 has samples at 0, 1, 2, 3, and 4. Dale B. Dalrymple

Posted by ●July 17, 2017

I'm saying that I have a signal which is some finite number of Dirac impuls= es on an integer time grid. Such a signal has a continuous Fourier transfor= m. This is well-known and different from a discrete-time signal that is sim= ply a sequence of unit-less numbers. I may have used the wrong terminology = for this signal but do you get the point? Bob

Posted by ●July 17, 2017

On Monday, July 17, 2017 at 4:33:05 PM UTC-4, radam...@gmail.com wrote:> I'm saying that I have a signal which is some finite number of Dirac impu=lses on an integer time grid. Such a signal has a continuous Fourier transf= orm. This is well-known and different from a discrete-time signal that is s= imply a sequence of unit-less numbers. I may have used the wrong terminolog= y for this signal but do you get the point? i might call that an "ideally-uniform-sampled signal". i think i know what = you mean. but i am having trouble understanding what the question is. the= best that i can understand your question, we have: 5 x_s(t) =3D SUM x[n] delta(t-nT) n=3D0 and you're multiplying x_s(t) times this rect window: w(t) =3D rect( (t - 2.5*T)/(4T) ) where rect(x) is the standard unit-wide rect centered at x=3D0. so the multiplied product is 5 x_s(t) w(t) =3D SUM{ x[n] delta(t-nT)} rect( (t - 2.5*T)/(4T) ) n=3D0 4 x_s(t) w(t) =3D SUM{ x[n] delta(t-nT)}=20 n=3D1 now what is the problem you're having, Bob? r b-j

Posted by ●July 18, 2017

Robert Thanks. I'm not really having any problem, this is a purely theoretic quest= ion.=20 The point I'm trying to make is that the width of the multiplying rect puls= e can vary continuously over some range and as long as it passes the same s= et of impulses, the FT of the result willl not change. But if I use the con= volution -in-the-frequency domain rule, I convolve with a sinc function, an= d depending on the width of the rect pulse (again, varied continuously over= some range that passes the same set of impulses), I will have Sinc functio= ns of varying "spread". So how do I explain using the convolution rule only= that I get a FT result that does not vary as the rect width varies? Bob

Posted by ●July 18, 2017

On Monday, July 17, 2017 at 9:27:46 PM UTC-4, radam...@gmail.com wrote:> Robert >=20 > Thanks. I'm not really having any problem, this is a purely theoretic que=stion.=20>=20 > The point I'm trying to make is that the width of the multiplying rect pu=lse can vary continuously over some range and as long as it passes the same= set of impulses, the FT of the result willl not change. But if I use the c= onvolution -in-the-frequency domain rule, I convolve with a sinc function, = and depending on the width of the rect pulse (again, varied continuously ov= er some range that passes the same set of impulses), I will have Sinc funct= ions of varying "spread". So how do I explain using the convolution rule on= ly that I get a FT result that does not vary as the rect width varies? it's a good question and similar to the reconstruction formula when the ban= dwidth is *known* to be less than the Nyquist frequency. Bob, do you do Stack Exchange yet? just like how markets change when somet= hing like Amazon comes on the scene, comp.dsp is becoming like Borders book= store. i might ask this question, (or the one that is more interesting to = me about reconstruction) on the dsp.se site. r b-j

Posted by ●July 18, 2017

On Monday, July 17, 2017 at 9:27:46 PM UTC-4, radam...@gmail.com wrote: \>=20> Thanks. I'm not really having any problem, this is a purely theoretic que=stion.=20>=20 > The point I'm trying to make is that the width of the multiplying rect pu=lse can vary continuously over some range and as long as it passes the same= set of impulses, the FT of the result willl not change. But if I use the c= onvolution -in-the-frequency domain rule, I convolve with a sinc function, = and depending on the width of the rect pulse (again, varied continuously ov= er some range that passes the same set of impulses), I will have Sinc funct= ions of varying "spread". So how do I explain using the convolution rule on= ly that I get a FT result that does not vary as the rect width varies?>=20so Bob, i spent about 80 minutes spiffying this up with LaTeX and the quest= ion (with me swapping time and frequency domains w.r.t. your question) is p= resented as in the DSP Stack Exchange: https://dsp.stackexchange.com/questions/42495/implication-of-sampling-and-r= econstruction-theorem=20 wanna look at that and make sure i don't misrepresent the question?

Posted by ●July 18, 2017

Thanks! Looks good to me, I think you're right that the dual problem occurs in reconstruction. Thanks for putting in the effort. Bob

Posted by ●July 18, 2017

On Tuesday, July 18, 2017 at 6:46:56 AM UTC-4, radam...@gmail.com wrote:> Thanks! > > Looks good to me, I think you're right that the dual problem occurs inreconstruction. Thanks for putting in the effort.>i really stripped the question down and asked it on the math Stack Exchange. https://math.stackexchange.com/questions/2362378/another-mathy-question-from-the-signal-processing-community it has an answer right away. the math guys have a notation that replaces the rect() or the unit step that i have to get used to. so i still haven't groked the whole thing yet. L8r, r b-j

Posted by ●July 18, 2017