Frequently Asked Questions (F.A.Q.)..... 1. (A Frequently Added Quotation, F.A.Q., is appended below.) Assuming that we were able to generate a Diracian, and then produce a comb of them by delays and by superposition, there wouldn't be a factor of "T" in such superposition, so where does yours come from? Where did the factor of "T" come from in the "sampling function" in your opening lines? Consider a 16-bit ADC capable of 100 M Samples per sec. In the first instance we'll use it to sample a geophysical signal of bandwidth limited to 300 HZ and sample at 1 kHz, with suitable analogue instrumentation to match the input signal to the full range of the ADC. If we keep the circuit the same, but now sample at 65.536 MHZ, your claimed factor of "T" will result in the 16 bit range being compressed down to one bit, because the new sampling frequency is 2^(16) faster than the old. We know this doesn't happen - there will be more samples, but they'll still be of the same magnitude and over the same full-scale 16-bit range. So, where does the factor of "T" come from? 2. Where have your Diracian impulses come from? The Diracian has some interesting properties - zero width, area of unity, infinite sum of all possible cosines, a height which is not discussed but which appears to be greater in magnitude than any voltage appearing in your circuits. In the systems that you deal with, what experimental evidence do you have that there are pulses with the attributes of Diracians upon which to base your theory? The Diracian, or Unit Impulse is a very good mathematical tool to analyse the response of systems once a mathematical model of those systems had been produced. It is, however, a poor mathematical claim to make that such impulses are found to be part of a system when neither the area nor the magnitude of such impulses are found anywhere in such systems. To those who ask, "Who cares? I get good results." , I suggest that their approach is unscientific and compares to the religious loonies who sacrifice goats and virgins to stop the Sun falling out of the sky and justify the continuing practice by the Sun remaining in the sky. So.....is the world of DSP a world of scientific men, or is it a world of snake-oil charlatans and of religious loonies? Where do these Diracian impulses come from?> robert bristow-johnson wrote: > > x(t)*q(t) = T*SUM{x[k]*d(t-k*T)} .------. > x(t)--->(*)------------------------------------->| H(f) |---> x(t) > ^ '------' > | > | +inf > '------- q(t) = T * SUM{ d(t - k*T) } > k=-inf > > > where: d(t) = 'dirac' impulse function > and T = 1/Fs = sampling period > Fs = sampling frequency > > > +inf > q(t) = T * SUM{ d(t - k*T) } is the "sampling function", is periodic > k=-inf with period T, and can be expressed as a > Fourier series. It turns out that ALL of > the Fourier coefficients are equal to 1.
FAQ - Perhaps there are real professionals here today rather than uppity technicians?
Started by ●November 18, 2005
Reply by ●November 18, 20052005-11-18
I think a dirac function is useful to develop math of sampling theory. To model a realistic stuation, we convolve a dirac function with a function that approximates to the real sampling function (which is likely to be some kind of average over a short time, perhaps weighted). The math supports this quite easily, but is not so easy to do, and in most cases the rsult is found ot be not much different. So we tend to work with the easy math rather than always using the hard stuff. However of course in many cases the non-dirac nature of sampling functions is important (for instance in image sensors which need to be quite large and so are averagers): in these cases we do take account of the sampling function (its effect in images is to attenuate certain spatial frequencies, which is easily demonstrated in practice). Chris ===================== Chris Bore BORES Signal Processing www.bores.com
Reply by ●November 18, 20052005-11-18
Polymath wrote:> Frequently Asked Questions (F.A.Q.)..... > > 1. (A Frequently Added Quotation, F.A.Q., is appended below.) > Assuming that we were able to generate a Diracian, and then produce > a comb of them by delays and by superposition, there wouldn't be a > factor > of "T" in such superposition, so where does yours come from? > > Where did the factor of "T" come from in the "sampling function" in > your opening lines? > > Consider a 16-bit ADC capable of 100 M Samples per sec. In the first > instance we'll use it to sample a geophysical signal of bandwidth > limited to 300 HZ and sample at 1 kHz, with suitable analogue > instrumentation to match the input signal to the full range of > the ADC. > > If we keep the circuit the same, but now sample > at 65.536 MHZ, your claimed factor of "T" will result in the > 16 bit range being compressed down to one bit, because the new > sampling frequency is 2^(16) faster than the old. We know this > doesn't happen - there will be more samples, but they'll still > be of the same magnitude and over the same full-scale 16-bit range. > to 1.So what you are asking is why does oversampling improve the resolution. Consider that the quantizing noise is distributed over the entire Nyquist bandwidth. When you raise the sampling rate, the Q noise is spread over a wider frequency range so the noise density is reduced and the noise in a given bandwidth of interest is reduced. The quantizing noise being distributed over the full Nyquist bandwidth depends on an assumpition of wideband random noise present at the input A/D input that excedds 1 LSB. This assumption can be met by the application of dither. Mark
Reply by ●November 18, 20052005-11-18
chris_bore@yahoo.co.uk wrote:> > I think a dirac function is useful to develop math of sampling theory. > To model a realistic stuation, we convolve a dirac function with a > function that approximates to the real sampling function (which is > likely to be some kind of average over a short time, perhaps weighted). > The math supports this quite easily, but is not so easy to do, and in > most cases the rsult is found ot be not much different. So we tend to > work with the easy math rather than always using the hard stuff. > However of course in many cases the non-dirac nature of sampling > functions is important (for instance in image sensors which need to be > quite large and so are averagers):This is nonsense. The primary problem with an image sensor is the signal being measured is not bandlimited. If the signal were in fact properly bandlimited then one could simply derive the signal magnitude at the exact center of each sensor in the array. In order to do that one must assume that each sensor is sized and located with perfect exactness. That is, of course, another real limitation to realizing the perfect sampling that the theory predicts. The width of the sensor is not. -jim in these cases we do take account of> the sampling function (its effect in images is to attenuate certain > spatial frequencies, which is easily demonstrated in practice). > > Chris > ===================== > Chris Bore > BORES Signal Processing > www.bores.com----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =----
Reply by ●November 19, 20052005-11-19
(Pseudonym changed from "Polymath", BTW) 1. How is it useful if it does not represent the engineering values being sampled? 2. Convolving with a Diracian is no more than multiplying by unity in the frequency domain - not a lot of use to anyone. 3. Thanks anyway. chris_bore@yahoo.co.uk wrote:> I think a dirac function is useful to develop math of sampling theory. > To model a realistic stuation, we convolve a dirac function with a > function that approximates to the real sampling function (which is > likely to be some kind of average over a short time, perhaps weighted). > The math supports this quite easily, but is not so easy to do, and in > most cases the rsult is found ot be not much different. So we tend to > work with the easy math rather than always using the hard stuff. > However of course in many cases the non-dirac nature of sampling > functions is important (for instance in image sensors which need to be > quite large and so are averagers): in these cases we do take account of > the sampling function (its effect in images is to attenuate certain > spatial frequencies, which is easily demonstrated in practice). > > Chris > ===================== > Chris Bore > BORES Signal Processing > www.bores.com
Reply by ●November 19, 20052005-11-19
No. What I am asking is, "Where did the factor of "T" come from in the "sampling function" in ... opening lines?" Mark wrote:> Polymath wrote: > > > > Where did the factor of "T" come from in the "sampling function" in > > your opening lines? > > > > So what you are asking is why does oversampling improve the resolution. >
Reply by ●November 19, 20052005-11-19
Dominus Dominorum wrote:> 2. Convolving with a Diracian is no more than multiplying > by unity in the frequency domainPrecisely. - not a lot of use to anyone. Maybe. But considerably more useful than attempting to multiply by anything else. -jim ----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =----
Reply by ●November 20, 20052005-11-20
>The primary problem with an image sensor is the signal >being measured is not bandlimited. If the signal were in fact properly >bandlimited then one could simply derive the signal magnitude at the >exact center of each sensor in the array. In order to do that one must >assume that each sensor is sized and located with perfect exactness. >That is, of course, another real limitation to realizing the perfect >sampling that the theory predicts. The width of the sensor is not.Are you saying that if the optical image were band-limited and we knew the exact size and sampling function of the sensor then we could reconstruct the signal at the center of the sensor? If so, then I agree with you but I do not see how that makes the statement that the sampling function is important be 'nonsense'. Also, surely there are many problems with image sensors apart from the fact that optical images are not bandlimited? Such as noise, light gathering power, that lead to a desire for large sensors, and sometimes microlenses - these mean the effective sampling function is not easy to assess perfectly. On the question of band limiting, an optical signal can be bandlimited with optical low pass filters - again, within the limitations of the technology but just as characterizable as antialias filters in any other domain. Chris ===================== Chris Bore BORES Signal Processing www.bores.com
Reply by ●November 20, 20052005-11-20
Polymath wrote:> Consider a 16-bit ADC capable of 100 M Samples per sec. In the first > instance we'll use it to sample a geophysical signal of bandwidth > limited to 300 HZ and sample at 1 kHz, with suitable analogue > instrumentation to match the input signal to the full range of > the ADC. > > If we keep the circuit the same, but now sample > at 65.536 MHZ, your claimed factor of "T" will result in the > 16 bit range being compressed down to one bit, because the new > sampling frequency is 2^(16) faster than the old.Do you assume the dimensions represented by the 16 bits of data word are the same in both cases and independant of sample rate? Why? Would a vector of samples of the geophysical signal stand on its own and be useful if the sample rate were completely unknown and undeduceable from just the vector contents? -- rhn
Reply by ●November 20, 20052005-11-20
chris_bore@yahoo.co.uk wrote:> > >The primary problem with an image sensor is the signal > >being measured is not bandlimited. If the signal were in fact properly > >bandlimited then one could simply derive the signal magnitude at the > >exact center of each sensor in the array. In order to do that one must > >assume that each sensor is sized and located with perfect exactness. > >That is, of course, another real limitation to realizing the perfect > >sampling that the theory predicts. The width of the sensor is not. > > Are you saying that if the optical image were band-limited and we knew > the exact size and sampling function of the sensor then we could > reconstruct the signal at the center of the sensor?We could but if we are talking ordinary photography we don't because we don't want to. Digital cameras can do a pretty good job of creating life-like images. For the signal they are intended to capture (that which the mind's eye would see) they are faithful. That is, the frequency response for the target signal is pretty flat. To change its "non-dirac nature" as you called it to more resemble a narrow pulse would degrade the result. Not because of issues with "noise, light gathering power" as you postulate but because it would change the frequency content of the signal. -jim> If so, then I agree with you but I do not see how that makes the > statement that the sampling function is important be 'nonsense'.> > Also, surely there are many problems with image sensors apart from the > fact that optical images are not bandlimited? > Such as noise, light gathering power, that lead to a desire for large > sensors, and sometimes microlenses - these mean the effective sampling > function is not easy to assess perfectly. > > On the question of band limiting, an optical signal can be bandlimited > with optical low pass filters - again, within the limitations of the > technology but just as characterizable as antialias filters in any > other domain. > > Chris > ===================== > Chris Bore > BORES Signal Processing > www.bores.com----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =----






