Hi all, I am told that there are Shannon Limit (Eb/No) with every code-rate BPSK modulation. Are there Shannon Limit (Eb/No) with every code-rate QAM(like 16QAM and 64QAM) modulation? Any suggestions will be appreciated! Best regards, Davy
QAM Shannon Limit?
Started by ●March 5, 2006
Reply by ●March 5, 20062006-03-05
Dear Davy, If you mean the theoretical curve of Eb/No versus the SNR. Then, yes, you have different curves for each modulation technique. Thanks Hany Davy wrote:> Hi all, > > I am told that there are Shannon Limit (Eb/No) with every code-rate > BPSK modulation. > > Are there Shannon Limit (Eb/No) with every code-rate QAM(like 16QAM and > 64QAM) modulation? > > Any suggestions will be appreciated! > > Best regards, > Davy
Reply by ●March 5, 20062006-03-05
Hi Hany, Thank you for your help. How can I get the theoretical curve of Eb/No versus the SNR? Shall I do some simulation? Best regards, Davy
Reply by ●March 5, 20062006-03-05
A few modulations have closed form solutions for their BER curves that you can plot, but most require simulation to generate. There are also plenty of curves that are approximate closed form solutions to the BER. Seems to me there's a cottage industry for generating curves that upper or lower bound the BER over various parts of the SNR axis. See "digital communications" by Proakis. -Clark "Davy" <zhushenli@gmail.com> wrote in message news:1141552227.847513.3260@p10g2000cwp.googlegroups.com...> Hi Hany, > > Thank you for your help. > > How can I get the theoretical curve of Eb/No versus the SNR? > Shall I do some simulation? > > Best regards, > Davy >
Reply by ●March 5, 20062006-03-05
"Davy" <zhushenli@gmail.com> wrote in message news:1141542441.288075.251580@z34g2000cwc.googlegroups.com...> Hi all, > > I am told that there are Shannon Limit (Eb/No) with every code-rate > BPSK modulation. > > Are there Shannon Limit (Eb/No) with every code-rate QAM(like 16QAM and > 64QAM) modulation? > > Any suggestions will be appreciated! >you could google for "shannon hartley" it may be what you are looking for. Best of luck - Mike