Why noise devided by two (N0/2) ? is it average value of noise +ve and
gaussian channel consider zero or white?
Reply by Randy Yates●March 6, 20062006-03-06
"Almas_Uddin_Ahmed" <email@example.com> writes:
> simple question
> Why noise devided by two (N0/2) ? is it average value of noise +ve and
I think it's just a convenience factor due to the way we normally
think about bandwidth.
Normally, if we say a signal has bandwidth B Hz, what we mean is
it is a) real, and b) non-zero from 0 to B Hz.
When working with the "complex baseband signal," such a signal has
non-zero energy from -B to +B. Thus if you have white noise PSD of
N0/2, and you integrate over -B to +B, you get the nice result that
the toal noise power is B*N0 watts.
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