PreWraping in Lead/Lag

Hello

I need to convert a lead/lag filter to a z transform function. I'll be 
using the bilinear method. 

Question, what equation do I use for prewraping the lead and lag times?? 
For the other filters i've converted i was prewrapping the frequency and 
using rads/sec. For the lead/lag filters I only have a time constant input.

Transfer function is 

      T1*s + 1
g(s) ----------
      T2*s + 1



Thanks

Toro wrote:
> Hello
> 
> I need to convert a lead/lag filter to a z transform function. I'll be 
> using the bilinear method. 
> 
> Question, what equation do I use for prewraping the lead and lag times?? 
> For the other filters i've converted i was prewrapping the frequency and 
> using rads/sec. For the lead/lag filters I only have a time constant input.
> 
> Transfer function is 
> 
>       T1*s + 1
> g(s) ----------
>       T2*s + 1

T = 1/ω = 1/2πf
-- 
Engineering is the art of making what you want from things you can get.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Jerry Avins <jya@ieee.org> wrote in news:bdWdnaHIL-VdyUbZnZ2dnUVZ_t-
dnZ2d@rcn.net:

> 
> T = 1/&#4294967295;% = 1/2&#4294967295; f
> -- 

That got real messed up in plain text, Jerry.

-- 
Scott
Reverse name to reply

Scott Seidman wrote:
> Jerry Avins <jya@ieee.org> wrote in news:bdWdnaHIL-VdyUbZnZ2dnUVZ_t-
> dnZ2d@rcn.net:
> 
>> T = 1/&#4294967295;% = 1/2&#4294967295; f
>> -- 
> 
> That got real messed up in plain text, Jerry.

UTF 8, Western (ISO8859-1)

Tau = 1/omega = 1/2pi*f

Thanks for the heads up.

Jerry
-- 
Engineering is the art of making what you want from things you can get.
&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;

Jerry Avins <jya@ieee.org> wrote in 
news:UJWdnbn2RsCXwEbZnZ2dnUVZ_rydnZ2d@rcn.net:

> Scott Seidman wrote:
>> Jerry Avins <jya@ieee.org> wrote in news:bdWdnaHIL-VdyUbZnZ2dnUVZ_t-
>> dnZ2d@rcn.net:
>> 
>>> T = 1/&#4294967295;% = 1/2&#4294967295; f
>>> -- 
>> 
>> That got real messed up in plain text, Jerry.
> 
> UTF 8, Western (ISO8859-1)
> 
> Tau = 1/omega = 1/2pi*f
> 
> Thanks for the heads up.
> 
> Jerry

Thanks for the response. Is the 'f' in Hz or in radians/sec? If in Hz 
then all I need to do is take the invers of T1 and T2 inputs, is this 
correct?

How about if in rad/sec, do I take the inverse and multiply by 2*pi??? Or 
am I missing something here??? 

thanks again

Toro wrote:
> Jerry Avins <jya@ieee.org> wrote in 
> news:UJWdnbn2RsCXwEbZnZ2dnUVZ_rydnZ2d@rcn.net:
> 
>> Scott Seidman wrote:
>>> Jerry Avins <jya@ieee.org> wrote in news:bdWdnaHIL-VdyUbZnZ2dnUVZ_t-
>>> dnZ2d@rcn.net:
>>>
>>>> T = 1/&#4294967295;% = 1/2&#4294967295; f
>>>> -- 
>>> That got real messed up in plain text, Jerry.
>> UTF 8, Western (ISO8859-1)
>>
>> Tau = 1/omega = 1/2pi*f
>>
>> Thanks for the heads up.
>>
>> Jerry
> 
> Thanks for the response. Is the 'f' in Hz or in radians/sec? If in Hz 
> then all I need to do is take the invers of T1 and T2 inputs, is this 
> correct?
> 
> How about if in rad/sec, do I take the inverse and multiply by 2*pi??? Or 
> am I missing something here??? 

f is cycles per second. w is radians per second. (It should really be ?; 
lower-case omega, but not everyone sees that properly.) w = 2*pi*f.
That's EE 101. Glad to help, but I assumed I didn't need to. My error.

Jerry
-- 
Engineering is the art of making what you want from things you can get.
&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;

Jerry Avins <jya@ieee.org> wrote in news:---
dnZc50eODBn_ZnZ2dnUVZ_o6dnZ2d@rcn.net:

> That's EE 101.


But if I had a dime for every time I've been off by a factor of 2pi ....

-- 
Scott
Reverse name to reply