DSPRelated.com
Forums

Confusion on bandwidth

Started by mathrookie August 15, 2006
I am confused by the relation between �data rate�, �frequency� and
�bandwidth�.
Let me explain my confusion with the following cases.
Case 1.  bandwidth is fixed, say �M�. There�re two frequency ranges. One
is from 0-M, the other is from M to 2M. Assume that all other conditions
such as modulation are the same. Who�s data rate is higher? 
Case 2. Assume that the second is from M to M+N where M/2 < N < M , then
who&#4294967295;s data rate is higher?



mathrookie wrote:
> I am confused by the relation between "data rate", "frequency" and > "bandwidth". > Let me explain my confusion with the following cases. > Case 1. bandwidth is fixed, say "M". There're two frequency ranges. One > is from 0-M, the other is from M to 2M. Assume that all other conditions > such as modulation are the same. Who's data rate is higher?
"Bandwidth" is a property of the channel. It is usually determined by the physics of the problem. Or these days, some political document stating how much bandwidth any one user is allowed to play with. "Modulation" is how you encode information into your signal. Different modulation schemes encode different amounts of information into the same bandwidth. "Data rate": The amount of information (bits or bytes per second) carried by a channel. This number is a function of both bandwidth and modulation scheme. So in your example, both channels have the same data rate.
> Case 2. Assume that the second is from M to M+N where M/2 < N < M , then > who's data rate is higher?
Since M+N < 2M then, according to the arguments above... ? Rune
mathrookie wrote:

> I am confused by the relation between &#4294967295;data rate&#4294967295;, &#4294967295;frequency&#4294967295; and > &#4294967295;bandwidth&#4294967295;.
> Let me explain my confusion with the following cases.
> Case 1. bandwidth is fixed, say &#4294967295;M&#4294967295;. There&#4294967295;re two frequency ranges. One > is from 0-M, the other is from M to 2M.
There is a factor of two that comes in, in some cases, which comes from the Fourier description as negative frequencies. When you say 0 to M some might say you mean -M to +M. At baseband the bandwidth is M, but upconverted it is 2M.
> Assume that all other conditions such as modulation are the same.
> Who&#4294967295;s data rate is higher? I would say it depends on the modulation method. Many modulation methods are practical today that weren't 20 or 50 years ago. AM radio, modulated with an audio signal, uses twice the necessary bandwidth to make demodulation easier. FM radio takes a 20kHz audio signal and expands it to 200kHz, among other reasons for better S/N ratio. AM doesn't make sense at baseband (your 0 to M example), though possibly if you mean M/2 +/- M/2.
> Case 2. Assume that the second is from M to M+N where M/2 < N < M , then > who&#4294967295;s data rate is higher?
Filtering is much easier with the carrier much higher than the bandwidth. Asking data rate questions without specifying a modulation method doesn't really make sense. -- glen
glen herrmannsfeldt wrote:
> mathrookie wrote: > > > I am confused by the relation between "data rate", "frequency" and > > "bandwidth".
"bandwidth" is real-estate on the electromagnetic spectrum.
> FM radio takes a 20kHz audio signal and expands it to 200kHz, > among other reasons for better S/N ratio.
current FM radio in the North America (87.9 -> 107.9 MHz) takes a 15 kHz bandlimited audio signal and expands it as you say (because FM is not linear modulation). FM-stereo has a big monster pilot signal (for L/R synchronization) at 19 kHz (and the baseband is as high as 53 kHz). dunno what it is in Europia or other parts of the world. r b-j
robert bristow-johnson wrote:
> glen herrmannsfeldt wrote: >> mathrookie wrote: >> >>> I am confused by the relation between "data rate", "frequency" and >>> "bandwidth". > > "bandwidth" is real-estate on the electromagnetic spectrum. > >> FM radio takes a 20kHz audio signal and expands it to 200kHz, >> among other reasons for better S/N ratio. > > current FM radio in the North America (87.9 -> 107.9 MHz) takes a 15 > kHz bandlimited audio signal and expands it as you say (because FM is > not linear modulation). FM-stereo has a big monster pilot signal (for > L/R synchronization) at 19 kHz (and the baseband is as high as 53 kHz). > dunno what it is in Europia or other parts of the world.
The 19 KHz is doubled to 38 to become the actual pilot. Don't forget the SCA channel that's there too. (Sometimes two.) Jerry -- Engineering is the art of making what you want from things you can get. &#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;
> >mathrookie wrote: >> I am confused by the relation between "data rate", "frequency" and >> "bandwidth". >> Let me explain my confusion with the following cases. >> Case 1. bandwidth is fixed, say "M". There're two frequency ranges.
One
>> is from 0-M, the other is from M to 2M. Assume that all other
conditions
>> such as modulation are the same. Who's data rate is higher? > >"Bandwidth" is a property of the channel. It is usually determined by >the physics of the problem. Or these days, some political document >stating how much bandwidth any one user is allowed to play with. > >"Modulation" is how you encode information into your signal. Different >modulation schemes encode different amounts of information into the >same bandwidth. > >"Data rate": The amount of information (bits or bytes per second) >carried by a channel. This number is a function of both bandwidth >and modulation scheme. > >So in your example, both channels have the same data rate. > >> Case 2. Assume that the second is from M to M+N where M/2 < N < M ,
then
>> who's data rate is higher? > >Since M+N < 2M then, according to the arguments above... ? > >Rune > >
May I argue like this? According to your definition of "Data rate", firstly we fix a simple phase-keying as modulation method, one sine wave represent bit "1" and the sine wave of the opposite phase stands for bit "0". However, we send the signal in different frequecies, first in "M" herz, while secondly in "1" herz. Starting from time 0, in one second, the first signal can carry theoretically as much as "M" bits. However, the second can only carry 1 bit.
robert bristow-johnson wrote:

> glen herrmannsfeldt wrote:
(snip)
>>FM radio takes a 20kHz audio signal and expands it to 200kHz, >>among other reasons for better S/N ratio.
> current FM radio in the North America (87.9 -> 107.9 MHz) takes a 15 > kHz bandlimited audio signal and expands it as you say (because FM is > not linear modulation). FM-stereo has a big monster pilot signal (for > L/R synchronization) at 19 kHz (and the baseband is as high as 53 kHz). > dunno what it is in Europia or other parts of the world.
If I remember it right, mono FM allows up to 20kHz. Stereo limited it to 15kHz into the multiplexer. Mono FM stations are rare these days, so it probably doesn't matter much. I thought the pilot was 10% modulation index, so it isn't that big. The amplitude limits on subcarriers approximately keep the overall bandwidth the same as for a 20kHz audio signal with no subcarriers. (Not counting that an FM signal theoretically has sidebands to infinity.) -- glen
mathrookie wrote:
> I am confused by the relation between "data rate", "frequency" and > "bandwidth". > Let me explain my confusion with the following cases. > Case 1. bandwidth is fixed, say "M". There're two frequency ranges. One > is from 0-M, the other is from M to 2M. Assume that all other conditions > such as modulation are the same. Who's data rate is higher? > Case 2. Assume that the second is from M to M+N where M/2 < N < M , then > who's data rate is higher?
I will try to remove your confusion by defining each term you have stated above. Also, for the sake of comprehensiveness, I will have to introduce another term called "symbol rate". I think the introduction of this term will increase your understanding on these terms and the relation between them. Bandwidth of a signal : The band width of any signal is defined as the range of frequencies where the signal strength is "appreciable". The exact interpretation of this "appreciable" strength various depending on the context where this signal is used and the commercial standards which this signal has to meet. Bandwidth of a channel: The band width of a channel is defined as the range of frequencies it can transmit without "apprecialbe" attenuation. The "appreciable" here holds the same meaning as above. Symbol: In any digital Communication scheme, data is sent in the form of symbols. Each symbol may represent one or more data elements ( this number can also be in fractions). The rate at which these symobols are sent is called the SYMBOL RATE and the rate at which the resulting data is sent is called the DATA RATE. Another important factor is the way the transition is made from one symbol to another. This method of transiton is called signal shaping or wave shaping. Both the symbol rate and the signal shape influence the bandwidth of a signal. (gradual transitions result in low bandwidth and low symbol rate result in low bandwidth). Carrier frequency: This is the frequency which is modulated by the sumbols. The bandwidth of the signal does not depend on this frequency. I hope this clears your confusion. Please feel free to contact me if there is any thing you don't understand in the above discussion or if you feel something is incorrect.
HarishKumar.Ch@gmail.com wrote:

   ...

> I hope this clears your confusion. Please feel free to contact me if > there is any thing you don't understand in the above discussion or if > you feel something is incorrect.
I would add to the fine explanation that "bandwidth" is often used erroneously to mean information-carrying capacity, and that is the source of much confusion. Even though the proverbial "boy on a bicycle" transporting a box of memory cards can move information across town as quickly as a microwave link, a bicycle is not a high-bandwidth device. Jerry -- Engineering is the art of making what you want from things you can get. &#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;&#4294967295;
HarishKumar.Ch@gmail.com wrote:
> mathrookie wrote: > > I am confused by the relation between "data rate", "frequency" and > > "bandwidth". > > Let me explain my confusion with the following cases. > > Case 1. bandwidth is fixed, say "M". There're two frequency ranges. One > > is from 0-M, the other is from M to 2M. Assume that all other conditions > > such as modulation are the same. Who's data rate is higher? > > Case 2. Assume that the second is from M to M+N where M/2 < N < M , then > > who's data rate is higher? > > I will try to remove your confusion by defining each term you have > stated above. Also, for the sake of comprehensiveness, I will have to > introduce another term called "symbol rate". I think the introduction > of this term will increase your understanding on these terms and the > relation between them. >
> Bandwidth of a signal : The band width of any signal is defined as the > range of frequencies where the signal strength is "appreciable". The > exact interpretation of this "appreciable" strength various depending > on the context where this signal is used and the commercial standards > which this signal has to meet.
Sometimes this is specifically constrained. The signal bandwidth of carrier grade voice is 3.4kHz, even though the original microphone will pick up a far wider bandwidth than this. The bandwidth of a signal is also sometimes stated as the required bandwidth for less than 3dB attenuation of the information signal. Much depends on the specifics of the signal you wish to deal with. It relates directly to the next item:
>> Bandwidth of a channel: The band width of a channel is defined as the > range of frequencies it can transmit without "apprecialbe" attenuation. > The "appreciable" here holds the same meaning as above. >
The bandwidth of a physical channel is _defined_ (for hardware) as the range of frequencies it can pass with less than 3dB attenuation. (Half power point). This can give rise to multiple transmission bands in a phyical channel. For a proper appreciation of channel characteristics, S parameters should be used.
> Symbol: In any digital Communication scheme, data is sent in the form > of symbols. Each symbol may represent one or more data elements ( this > number can also be in fractions). The rate at which these symobols are > sent is called the SYMBOL RATE and the rate at which the resulting data > is sent is called the DATA RATE. Another important factor is the way > the transition is made from one symbol to another. This method of > transiton is called signal shaping or wave shaping. Both the symbol > rate and the signal shape influence the bandwidth of a signal. (gradual > transitions result in low bandwidth and low symbol rate result in low > bandwidth).
The symbol rate of a channel is also the baud rate (surely one of the most abused terms in the history of electronics). Trivia: a 2400 bps telephone line modem (using 16 QAM) has a baud rate of 600 (600 symbols / sec).
> > Carrier frequency: This is the frequency which is modulated by the > sumbols. The bandwidth of the signal does not depend on this frequency.
> > > I hope this clears your confusion. Please feel free to contact me if > there is any thing you don't understand in the above discussion or if > you feel something is incorrect.
Cheers PeteS