Hi I need to take a standard 8bit ADC which samples at 40Msps increase the resolution by about 4 or 5 bits. I know that oversampling spreads the quantization noise over a wider bandwidth thereby decreasing the SQNR. So i can increase the resolution through decimation? How do I increase the resolution through decimation? It decimates the signal frequency but i don't physically know how to increase it because if i send 8 bits in i should just receive 8 bits out? Please help. Thank you very much. _____________________________________ Do you know a company who employs DSP engineers? Is it already listed at http://dsprelated.com/employers.php ?

# Increase resolution through decimation

Started by ●May 28, 2007

Posted by ●May 28, 2007

mariking wrote:> Hi > > I need to take a standard 8bit ADC which samples at 40Msps increase the > resolution by about 4 or 5 bits. I know that oversampling spreads the > quantization noise over a wider bandwidth thereby decreasing the SQNR. So > i can increase the resolution through decimation? How do I increase the > resolution through decimation? It decimates the signal frequency but i > don't physically know how to increase it because if i send 8 bits in i > should just receive 8 bits out?With a small amount of noise present in or added to the input signal (AND PROVIDED THAT THE LINEARITY OF THE CONVERTER IS 12 BITS ACCURATE) the the average of N readings has sqrt(N) better precision, making it worth keeping log2(n) more bits. If you keep the most significant 12 bits from the sum of 256 dithered readings taken in quick succession you can expect them to be reasonably accurate. The extra 4 bits represent an accuracy improvement of 16:1, for which you pay with a total of 16^2 readings. Jerry -- Engineering is the art of making what you want from things you can get. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Posted by ●May 28, 2007

"Jerry Avins" <jya@ieee.org> wrote in message news:ca6dnRjSZ4rEYMfbnZ2dnUVZ_o2vnZ2d@rcn.net...> mariking wrote: >> Hi >> >> I need to take a standard 8bit ADC which samples at 40Msps increase the >> resolution by about 4 or 5 bits. I know that oversampling spreads the >> quantization noise over a wider bandwidth thereby decreasing the SQNR. So >> i can increase the resolution through decimation? How do I increase the >> resolution through decimation? It decimates the signal frequency but i >> don't physically know how to increase it because if i send 8 bits in i >> should just receive 8 bits out? > > With a small amount of noise present in or added to the input signal (AND > PROVIDED THAT THE LINEARITY OF THE CONVERTER IS 12 BITS ACCURATE) the the > average of N readings has sqrt(N) better precision, making it worth > keeping log2(n) more bits. If you keep the most significant 12 bits from > the sum of 256 dithered readings taken in quick succession you can expect > them to be reasonably accurate. The extra 4 bits represent an accuracy > improvement of 16:1, for which you pay with a total of 16^2 readings. > > Jerry > --And, a minor point, you don't get 8 bits out for 8 bits in because of the addition of many samples in the decimation filtering. That is, in order to properly decimate, you need to first lowpass filter. The lowpass filter is implemented with a number of multiplies and adds. The simplest lowpass filter is a simple averager. Thus, no multiplies but still probably many adds. Thus more bits at the output. Fred

Posted by ●May 28, 2007

Fred Marshall wrote:> "Jerry Avins" <jya@ieee.org> wrote in message > news:ca6dnRjSZ4rEYMfbnZ2dnUVZ_o2vnZ2d@rcn.net... >> mariking wrote: >>> Hi >>> >>> I need to take a standard 8bit ADC which samples at 40Msps increase the >>> resolution by about 4 or 5 bits. I know that oversampling spreads the >>> quantization noise over a wider bandwidth thereby decreasing the SQNR. So >>> i can increase the resolution through decimation? How do I increase the >>> resolution through decimation? It decimates the signal frequency but i >>> don't physically know how to increase it because if i send 8 bits in i >>> should just receive 8 bits out? >> With a small amount of noise present in or added to the input signal (AND >> PROVIDED THAT THE LINEARITY OF THE CONVERTER IS 12 BITS ACCURATE) the the >> average of N readings has sqrt(N) better precision, making it worth >> keeping log2(n) more bits. If you keep the most significant 12 bits from >> the sum of 256 dithered readings taken in quick succession you can expect >> them to be reasonably accurate. The extra 4 bits represent an accuracy >> improvement of 16:1, for which you pay with a total of 16^2 readings. >> >> Jerry >> -- > > And, a minor point, you don't get 8 bits out for 8 bits in because of the > addition of many samples in the decimation filtering. > That is, in order to properly decimate, you need to first lowpass filter. > The lowpass filter is implemented with a number of multiplies and adds. The > simplest lowpass filter is a simple averager. Thus, no multiplies but still > probably many adds. Thus more bits at the output.I once had an Analog Devices programmable data acquisition system that offered 12- or 16-bit conversions. The shorter conversions were done with a successive-approximation converter at high speed. The 16-bit conversions were about as fast as the integrating converters of the day. (16- and 18- bit conversions were typically done with dual-slope converters.) In fact there was only one A/D on the system. a 12-bit converter with 16-bit precision on the bit transitions. To get a 12-bit reading, noise with a triangular distribution was added to the input, and a burst of 265 readings added to an accumulator. If all the bits had been kept, that could have resulted in as many as 24 bits, depending on the reading. The low 8 bits were discarded after addition was complete, yielding the 16-bit result. Since the signal being measured was made stationary by the sample-and-hold, an appropriate ramp could have replaces the "noise". When a measuring instrument is far more accurate than the uncertainty introduced by independent measurement errors, the accuracy of a series of averaged readings increases with the square root of their number. I don't know how replacing the average with a another kind of low-pass filter affects the outcome. Jerry -- Engineering is the art of making what you want from things you can get. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯