I am reading a paper about fixed point implementation. The author has given an example for input range estimation for multi user detection. It is said "From the characteristic of the Gold code, we know that the maximum value of cross-correlation coefficients is the auto correlation of any particular spreading sequence,i.e., rang R is R=2x(2^r-1), where the spreading gain is 2^r-1". I can understand the maximum value part but I don't know how to deduce the range estimation is 2 x (spreading gain). Is there anybody explain to me? Many thanks.
About range estimation for fixed point implementation
Started by ●November 10, 2007
Reply by ●November 10, 20072007-11-10
Zhi <threeinchnail@gmail.com> writes:> I am reading a paper about fixed point implementation. The author has > given an example for input range estimation for multi user detection. > It is said "From the characteristic of the Gold code, we know that the > maximum value of cross-correlation coefficients is the auto > correlation of any particular spreading sequence,i.e., rang R is > R=2x(2^r-1), where the spreading gain is 2^r-1". I can understand the > maximum value part but I don't know how to deduce the range estimation > is 2 x (spreading gain). Is there anybody explain to me? Many thanks.My guess is that they're allowing for the possibility that one of the codes is inverted in polarity, so that you can get values from -1*(2^r - 1) <= x <= +1*(2^r - 1). -- % Randy Yates % "With time with what you've learned, %% Fuquay-Varina, NC % they'll kiss the ground you walk %%% 919-577-9882 % upon." %%%% <yates@ieee.org> % '21st Century Man', *Time*, ELO http://www.digitalsignallabs.com