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Hi friends, we have a problem. We've an image of 576x768 pixels reconstructed with a CCD camera of 6.35x7.4 micron/pixel. We need make the image FFT2 to know the frequencies of that. We need make a change of phase of Fourier transform of the image because we need make adimensional the exponential of Fourier Transform. For this, we need the formula of the Fourier Transform of Matlab and en explanation of the variables of the FFT2. We use this formula: exp(-j*2*pi*(x*u+y*v)/(l*fo)) where 'u' is the pixel coordinates. 'l' is the wavelength (cm.) 'fo' is the focal of our 4f Fourier System (cm.) In this formula we make (x*u*x0+y*v*y0) where 'x0' and 'y0' are the camera pixels dimensions (6.35x7.4)to have cm in the numerator. Like the exponential must be adimensional, we need to know what are x and y to have cm^2 in the numerator. Sorry by my english and thanks for your help. Bye. |
FFT2 question
Started by ●April 1, 2004
