I have an image .
how can I have a dct transform of this image.
I want to access to dct coofisients.
how can I have a dct transform of this image?
Started by ●June 19, 2009
Reply by ●June 23, 20092009-06-23
Hi Ali,
It is so easy to convert an image from spatial domain to frequncy domain using DCT
You have to way to do that; first by apply DCT to full fram image
for eaxmple,
1- read an image
im1= imread('lena.jpg');
2- apply DCT as
im1_dct= dct2(im1);
you will get dct coefficients in im1_dct
you should know that the first coefficient is DC coefficients following by AC coefficients.
second choice you can apply DCT in blocj of 8*8 (as jpeg compression algorithm)
select a block of 8*8 from the image and apply the DCT into that block as
Hope this little help
By the way you can have some examples from matlab exchanhe website.
Regards,
Ibrahim Nasir
--- On Fri, 6/19/09, ali_khodaie2002 wrote:
From: ali_khodaie2002
Subject: [matlab] how can I have a dct transform of this image?
To: m...
Date: Friday, June 19, 2009, 12:54 AM
I have an image .
how can I have a dct transform of this image.
I want to access to dct coofisients.
It is so easy to convert an image from spatial domain to frequncy domain using DCT
You have to way to do that; first by apply DCT to full fram image
for eaxmple,
1- read an image
im1= imread('lena.jpg');
2- apply DCT as
im1_dct= dct2(im1);
you will get dct coefficients in im1_dct
you should know that the first coefficient is DC coefficients following by AC coefficients.
second choice you can apply DCT in blocj of 8*8 (as jpeg compression algorithm)
select a block of 8*8 from the image and apply the DCT into that block as
Hope this little help
By the way you can have some examples from matlab exchanhe website.
Regards,
Ibrahim Nasir
--- On Fri, 6/19/09, ali_khodaie2002 wrote:
From: ali_khodaie2002
Subject: [matlab] how can I have a dct transform of this image?
To: m...
Date: Friday, June 19, 2009, 12:54 AM
I have an image .
how can I have a dct transform of this image.
I want to access to dct coofisients.