John Smith (@johnny_smith911)
The 1st cycle has a frequency of 100 Hz & fits perfectly in the N = 1000 samples window, i.e a full cycle of 100 Hz with nothing less or more fitting perfectly...
Yes, I think both methods should give the same result & the second method should be computationally more efficient.However, both these methods I believe, are...
Exactly. Some sort of compensation needs to be done while shifting from the old cycle to the new one to account for the difference in the window lengths while...
Hi Rick,Thanks for your reply. Let me explain the algorithm that I'm using.1. Keep acquiring samples until one full cycle is complete (using zero crossings to detect...
Hi Kaz,I do know the new frequency after the deviation & yes, I do resize the window. However, this is just one part of the problem(albeit the easy one).The...
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