Analog IIR Butterworth Filter - Scilab
To Design an Analog Butterworth Filter For the given cutoff frequency Wc = 500 Hz and filter order
// To Design an Analog Butterworth Filter
//For the given cutoff frequency and filter order
//Wc = 500 Hz
omegap
= 500; //pass band edge frequency
omegas
= 1000;//stop band edge frequency
delta1_in_dB
= -3;//PassBand Ripple in dB
delta2_in_dB
= -40;//StopBand Ripple in dB
delta1
= 10^
(delta1_in_dB
/20)
delta2
= 10^
(delta2_in_dB
/20)
//Caculation of filter order
N
= log10((1/(delta2^
2))-1)/(2*log10(omegas
/omegap
))
N
= ceil(N
) //Rounding off nearest integer
omegac
= omegap
;
h
=buttmag(N
,omegac
,1:1000);//Analog Butterworth filter magnitude response
mag
=20*log10(h
);//Magntitude Response in dB
plot2d((1:1000),mag
,[0,-180,1000,20]);
a
=gca();
a.thickness
= 3;
a.foreground
= 1;
a.font_style
= 9;
xgrid(5)
xtitle('Magnitude Response of Butterworth LPF Filter Cutoff frequency = 500 Hz','Analog frequency in Hz--->','Magnitude in dB -->');
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posted by Senthilkumar R