CTFS coefficients of a periodic square waveform
This program is used to calculate the CTFS coefficients of a periodic square waveform
x(t) = 1, |t|<1, and 0, 1<|t|<2
//CTFS coefficients of a periodic square waveform
//x(t) = 1, |t|<T1, and 0, T1<|t|<T/2
clear;
close;
clc;
T
=4;
T1
= T
/4;
t
= -T1
:T1
/100:T1
;
Wo
= 2*%pi/T
;
xt
=ones(1,length(t
)); //Square Wave Generation
//Finding the Fourier Series Coefficients
for k
=0:5
C
(k
+1,:) = exp(-sqrt(-1)*Wo
*t.
*k
);
a
(k
+1) = xt
*C
(k
+1,:)'/length(t
);
if(abs(a
(k
+1))<=0.1)
a
(k
+1)=0;
end
end
a
=a
';
a_conj
= real(a
(:))-sqrt(-1)*imag(a
(:));
ak
= [a_conj
($
:-1:1)',a
(2:$
)];
k
= 0:5;
k
= [-k
($
:-1:1),k
(2:$
)];
Spectrum_ak
= (1/2)*real(ak
);
//Plotting the Continuous Time Signal
figure
a
= gca();
a.y_location
= "origin";
a.x_location
= "origin";
a.data_bounds
=[-2,0;2,2];
plot2d2(t
,xt
,5)
poly1
= a.children
(1).children
(1);
poly1.thickness
= 3;
title('x(t)')
xlabel
(' t')
//Plotting the Spectral coefficients of CT Signal
figure
a
= gca();
a.y_location
= "origin";
a.x_location
= "origin";
plot2d3('gnn',k
,Spectrum_ak
,5)
poly1
= a.children
(1).children
(1);
poly1.thickness
= 3;
title('abs(ak)')
xlabel
(' k')
//Result
//Spectrum_ak =
//0.0633127 0. -0.1055559 0. 0.3167197 0.5 0.3167197 0. -0.1055559 0. 0.0633127
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posted by Senthilkumar R