It still has period N in the time domain.
Are you referring to the x1(n) sequence given in the answer?
In this case, the time-domain sequences referred to here are only defined for N samples in the time domain. So, they are not "periodic" in the normal sense of the word, since any periodic signal (other than the zero signal) must be infinite in extent.
The meaning of the term "periodic" in this context is defined in the example given just above the question, as a sequence that has:
"periodically repeating sample values"
This seems to be interpreted as no sample values must repeat. Another way to phrase the question would be:
True or False:
"All real-valued N-sample sinusoidal sequences containing an integer number of cycles, and having a DFT with only two non-zero spectral components, will necessarily have repeating sample values."
Another counterexample would be the 4-sample sequence:
n = 0,...,3.
which is given by:
i.e. just one cycle.
You are correct. The college textbook definition of a "periodic" sequence, of period N, is a sequence that satisfies:
x(n + N) = x(n), for all n.
Your length N = 4 example, cos(2*pi*n/4+pi/3), has a period of P = 4. But to be time-domain periodic (periodically repeating sample values) its period P must less than N. So, indeed, your cos(2*pi*n/4+pi/3) is not time-domain periodic.
Hi Eric. Hope you're doing well.
Please see my below Reply to Micael Collins' Comment.
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