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Infinite Flatness at Infinity
The Gaussian is infinitely flat at infinity. Equivalently, the
Maclaurin expansion (Taylor expansion about
) of
is
zero for all orders. Thus, even though

is
differentiable of all orders at

, its
series expansion fails to
approach the function. This happens because

has an
essential singularity at

(also called a
``non-removable singularity''). One can think of an essential
singularity as an infinite number of
poles piled up at the same
point (

for

). Equivalently,

above has an
infinite number of zeros at

, leading to the problem with
Maclaurin series expansion. To prove this, one can show
for all

. This follows from the fact that
exponential
growth or decay is faster than polynomial growth or decay. An
exponential can in fact be viewed as an infinite-order polynomial,
since
We may call
infinitely flat at

in the ``
Padé sense'':
Another interesting mathematical property of essential singularites is
that near an essential singular point
the
inequality
is satisfied at some point

in
every neighborhood of

, however small. In other words,

comes arbitrarily close
to
every possible value in
any neighborhood about an
essential singular point. This was first proved by Weierstrass
[
41, p. 270].
Previous: Fitting a Gaussian to DataNext: Integral of a Complex Gaussian
About the Author: Julius Orion Smith III
Julius Smith's background is in electrical engineering (BS Rice 1975, PhD Stanford 1983). He is presently Professor of Music and Associate Professor (by courtesy) of Electrical Engineering at
Stanford's Center for Computer Research in Music and Acoustics (CCRMA), teaching courses and pursuing research related to signal processing applied to music and audio systems. See
http://ccrma.stanford.edu/~jos/ for details.