## Zero Crossing Counter

In some DSP applications, it can be very helpful to know how many times your signal has crossed the zero-line (amplitude origin).

How is this helpful? Well, zero-crossings can tell you very quickly if your signal is composed of high frequency content or not. Let's say your sample rate is 50kHz and over a small window of 1,000 samples there are 500 zero-crossings. That would mean that every two samples crosses the zero-line (i.e. 12.5kHz)

In speech processing, the zero-crossing counts can help distinguish between voiced and un-voiced speech. Un-voiced sounds are very noise-like ('Shh' and 'Sss' for example). In addition, zero-crossings could also be used to determine if your signal has a DC offset. If you signal is 'muted' and you are not seeing alot of zero-crossings might mean that your signal is offset from the zero-line

One nice thing about the matlab code below is that it is implemented in a very DSP-friendly way. It ports very easily into C-Code and does minimizes the amount of conditional statements for faster processing time.

```
function count = zero_crossings(x)
% Count the number of zero-crossings from the supplied time-domain
% input vector. A simple method is applied here that can be easily
% ported to a real-time system that would minimize the number of
% if-else conditionals.
%
% Usage: COUNT = zero_crossings(X);
%
% X is the input time-domain signal (one dimensional)
% COUNT is the amount of zero-crossings in the input signal
%
% Author: sparafucile17 06/27/04
%
% initial value
count = 0;
% error checks
if(length(x) == 1)
error('ERROR: input signal must have more than one element');
end
if((size(x, 2) ~= 1) && (size(x, 1) ~= 1))
error('ERROR: Input must be one-dimensional');
end
% force signal to be a vector oriented in the same direction
x = x(:);
num_samples = length(x);
for i=2:num_samples
% Any time you multiply to adjacent values that have a sign difference
% the result will always be negative. When the signs are identical,
% the product will always be positive.
if((x(i) * x(i-1)) < 0)
count = count + 1;
end
end
```