Mass Moment of Inertia as a Cross Product
In Eq.(B.14) above, the mass moment of inertia was expressed
in terms of orthogonal projection as
, where
. In terms of the vector cross
product, we can now express it as
![$\displaystyle I \eqsp m\cdot(\underline{\tilde{\omega}}\times \underline{x})^2 ...
...cdot\sin(\theta_{\underline{\tilde{\omega}}\underline{x}})\right]^2
\eqsp mR^2
$](http://www.dsprelated.com/josimages_new/pasp/img2845.png)



Next Section:
Tangential Velocity as a Cross Product
Previous Section:
Cross-Product Magnitude