# Specifying the Maximum Amplifier Noise When Driving an ADC

I recently learned an interesting rule of thumb regarding the use of an amplifier to drive the input of an analog to digital converter (ADC). The rule of thumb describes how to specify the maximum allowable noise power of the amplifier [1].

**The Problem**

Here's the situation for an ADC whose maximum analog input voltage range is –*V*_{Ref} to +*V*_{Ref}. If we drive an ADC's analog input with an sine wave whose peak amplitude is *V*_{P} = *V*_{Ref}, the ADC's output signal to noise ratio is maximized. We'll call that maximum signal to noise ratio *SNR*_{Max}. That scenario is shown in Figure 1(a).

If, on the other hand, we drove an ADC's analog input with an sine wave whose peak amplitude is *V*_{P} = *V*_{Ref}/α, where α > 1, the ADC's output signal to noise ratio will be less than *SNR*_{Max}. That scenario is shown in Figure 1(b). In this case we're not driving the ADC to its full-scale analog input range and we'll call this output signal to noise ratio *SNR*_{No Amp} < *SNR*_{Max}. Because we're not utilizing the full-scale analog input range of the ADC, we're losing potential ADC output signal to noise ratio.

To overcome that loss of output signal to noise ratio in Figure 1(b) we can use an amplifier, with a voltage gain of α, to drive the ADC's input to fullscale as shown in Figure 1(c). We'll use the variable *SNR*_{With Amp} to represent the ADC output signal to noise ratio in this case. However, we must be cautious! Because we cannot buy an ideal noise-free amplifier at Radio Shack, we're forced to use an amplifier that has some non-zero output noise. In that case, the question becomes, "What is the maximum inherent amplifier noise we can tolerate and still ensure that *SNR*_{With Amp} > *SNR*_{No Amp}?" And the answer to that question is the point I'm attempting to make in this blog. Please read on.

**ADC Quantization Noise**

Just to remind you, the quantization noise power of an *b*-bit ADC, whose maximum analog input voltage range is –*V*_{Ref} to +*V*_{Ref}, is:

where *q* is the least significant bit (LSB) voltage range equal to

Equation (1) is based on the assumption that the ADC's input voltage crosses 4 or 5 LSB voltage boundaries, and is not synchronous with the ADC's sample frequency. The derivation of Eq. (1) is readily available on the Internet and in just about every DSP textbook.

**ADC Output Signal to Noise Ratio**

In the Figure 1(a) case, the ADC's output signal to noise ratio, in decibels, is:

In the Figure 1(b) case, the ADC's output signal to noise ratio is:

In the Figure 1(c) case, the ADC's output signal to noise ratio is:

Because in Figure 1(c) we're driving the ADC to full-scale the numerator of the ratio in *SNR*_{With Amp} in Eq. (5) is equal to the numerator of the ratio in *SNR*_{Max} in Eq. (3). The denominator of the ratio in Eq. (5) is ADC quantization noise power plus the amplifier's output noise power. The term *V*_{Amp Noise} in Eq. (5) is the RMS of the amplifier's inherent internally-generated noise __ referred to the input of the amplifier__. Thus the term α

^{2}(

*V*

_{Amp Noise})

^{2}is the amplifier's output noise power.

For a given ADC with an input signal that requires amplification by a gain of α, we want to know what is the maximum value of (*V*_{Amp Noise})^{2} so that *SNR*_{With Amp} is greater than *SNR*_{No Amp}? To answer that question we must compare Eqs. (4) and (5). We can make that comparison by first multiplying Eq. (4)'s numerator and denominator ratios by α^{2} giving us:

Now we can easily compare Eqs. (5) and (6) because they have identical numerator ratios. So all we have to do to make sure that *SNR*_{With Amp} is greater than *SNR*_{No Amp} is ensure that the denominator of Eq. (5) is less than the denominator of Eq. (6). That is, we want the following inequality to be satisfied:

Rearranging Eq. (7), we want to ensure that the following inequality is satisfied:

So there we have it. We want the amplifier's internally-generated noise power, *referred to the input of the amplifier*, to be a factor of (1-1/α^{2}) less than the ADC's *q*^{2}/12 quantization noise power.

It's instructive to plot the maximum (*V*_{Amp Noise})^{2} in percentage terms of the ADC's *q*^{2}/12 quantization noise power, as a function of amplifier gain α. We do that in Figure 2.

We interpret Figure 2 as follows: let's say our original analog input signal requires a voltage gain of α = 2 to drive an ADC to full-scale. For a value of α = 2, Figure 2 and Eq. (8) tell us that (*V*_{Amp Noise})^{2} must be no greater than 75% of the ADC's *q*^{2}/12 quantization noise power.

When I first looked at Figure 2 I noticed that it implied: for larger values of amplifier gain a larger values of (*V*_{Amp Noise})^{2} are acceptable. That means for larger values of a larger values of α^{2} (*V*_{Amp Noise})^{2} amplifier output noise power are tolerable. This didn't make sense to me until I realized: for larger values of gain a the value of *SNR*_{No Amp} will be smaller permitting larger acceptable maximum values for (*V*_{Amp Noise})^{2} as shown in Figure 3.

**Conclusion**

Given the specifications of an ADC and the necessary gain of an amplifier, Eq. (8) and Figure 2 tell us what must be the maximum amplifier output noise so that using an amplifier improves an ADC's output SNR relative to not using an amplifier. By the way, Reference [2] presents a useful tutorial on amplifier noise.

**References**

[1] This amplifier noise rule of thumb was taught to me by Prof. Ayman Fayed, ADC guru at Iowa State University.

[2] Analog Devices web page: http://www.analog.com/static/imported-files/rarely_asked_questions/moreInfo_raq_opAmpNoise2.html

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## Comments:

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alpha > 1

It seems that the second half of you post failed to show up in your comment. I'm not sure what is the point you're trying to make. In any case, if alpha a <1 then we'd need an attenuator preceding the ADC, rather than an amplifier, to avoid overdriving the ADC.

[-Rick-]

i think abara meant that there is an error in you text: in your text ther is the sentence as abara has mentioned.It shall be "alpha>1"

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