The DFT

For a length $ N$ complex sequence $ x(n)$, $ n=0,1,2,\ldots,N-1$, the discrete Fourier transform (DFT) is defined by

$\displaystyle X(\omega_k) \isdef \sum_{n=0}^{N-1}x(n) e^{-j\omega_k t_n} = \sum_{n=0}^{N-1}x(n) e^{-j 2\pi kn/N},
\quad k=0,1,2,\ldots N-1
$

\begin{eqnarray*}
t_n &\isdef & nT = \mbox{$n$th sampling instant (sec)} \\
\om...
...sdef & 2\pi f_s/N = \mbox{frequency sampling interval (rad/sec)}
\end{eqnarray*}

We are now in a position to have a full understanding of the transform kernel:

$\displaystyle e^{-j\omega_k t_n} = \cos(\omega_k t_n) - j \sin(\omega_k t_n)
$

The kernel consists of samples of a complex sinusoid at $ N$ discrete frequencies $ \omega_k$ uniformly spaced between 0 and the sampling rate $ \omega_s \isdeftext 2\pi f_s$. All that remains is to understand the purpose and function of the summation over $ n$ of the pointwise product of $ x(n)$ times each complex sinusoid. We will learn that this can be interpreted as an inner product operation which computes the coefficient of projection of the signal $ x$ onto the complex sinusoid $ \cos(\omega_k t_n) + j \sin(\omega_k t_n)$. As such, $ X(\omega_k)$, the DFT at frequency $ \omega_k$, is a measure of the amplitude and phase of the complex sinusoid which is present in the input signal $ x$ at that frequency. This is the basic function of all linear transform summations (in discrete time) and integrals (in continuous time) and their kernels.


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Sinusoid Problems