Hi

how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the
integer part and the fractional part and combine the result.

Regards,

Mayank

# Floating point division

Started by ●April 6, 2013

Reply by ●April 6, 20132013-04-06

Mayank,

Perhaps if you explained why you are wanting to handle the integer and

fractional part separately, we could be of more help.

Are you actually trying to perform Fixed Point math?

The following code performs that you say you are asking for, but the result is

meaningless:

int integer1;

int fraction1;

int integer2;

int fraction2;

float result1;

float result2:

float integer3;

float integer4

float final;

integer1 = floor(4.2);

integer2 = floor(2.35);

fraction1 = 100*(4.2-integer1);

fraction2 = 100*(2.35-integer2);

result1 = integer1/integer2;

result2 = fraction1/fraction2;

final = result1+(result2/100);

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: "c..."

Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

Subject: [c6x] Floating point division

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> separately the integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

------- End of Original Message -------

_____________________________________

Perhaps if you explained why you are wanting to handle the integer and

fractional part separately, we could be of more help.

Are you actually trying to perform Fixed Point math?

The following code performs that you say you are asking for, but the result is

meaningless:

int integer1;

int fraction1;

int integer2;

int fraction2;

float result1;

float result2:

float integer3;

float integer4

float final;

integer1 = floor(4.2);

integer2 = floor(2.35);

fraction1 = 100*(4.2-integer1);

fraction2 = 100*(2.35-integer2);

result1 = integer1/integer2;

result2 = fraction1/fraction2;

final = result1+(result2/100);

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: "c..."

Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

Subject: [c6x] Floating point division

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> separately the integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

------- End of Original Message -------

_____________________________________

Reply by ●April 6, 20132013-04-06

mayank,

with float a; and float b:

you should be able to simply say.

float c = a/b;

then the compiler will perform the math using floating point.

Note;

if the DSP is fixed point, then you will need to include a floating point

library, both at compile time '#include ' and '#include '

and at link time '-lm'

Note:

The floating point libraries are very large.

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: Richard Williams

Cc: "c..."

Sent: Sat, 6 Apr 2013 08:23:40 -0700 (PDT)

Subject: Re: [c6x] Floating point division

> Hi Richard,

>

> Thanks for your mail.The problem is like that gien below.

>

> Let's say, I give you a function called div_int which takes two

> integer arguments, x and y and gives a result which is the integer

> divisionof the two numbers. E.g. if x = 4 and y = 2 the answer is 2.

> If x = 5 and y = 2 the answer is 2. If x = 10 and y = 3 the answer is

> 3 etc.

>

> How will you use this div_int function to compute floating point divisions?

>

> Here is part of the C-code

>

> void main(void)

> {

> float a = 0.1;

> float b = 0.2; // Do the same thing with a = 4.2 and b = 2.35

>

> // fill in the blanks

> _____;

> .

> .

> .

> _____;

> __ = div_int(__, __); // fill in the blanks

>

> // fill in some more blanks

> ______;

> .

> .

> .

> ______;

>

> printf("The integer part of the divisionis %d and the fractional

> part of the divisionis %d\n", __, __); // fill in the blanks }

>

> Thanks and Regards

> Mayank

>

> ________________________________

> From: Richard Williams

> To: mayank agarwal ; "c..."

> Sent: Saturday, April 6, 2013 8:40 PM Subject:

> Re: [c6x] Floating point division

>

> Mayank,

>

> Perhaps if you explained why you are wanting to handle the integer and

> fractional part separately, we could be of more help.

>

> Are you actually trying to perform Fixed Point math?

>

> The following code performs that you say you are asking for, but the

> result is meaningless:

>

> int integer1;

> int fraction1;

>

> int integer2;

> int fraction2;

>

> float result1;

> float result2:

>

> float integer3;

> float integer4

>

> float final;

>

> integer1 = floor(4.2);

> integer2 = floor(2.35);

>

> fraction1 = 100*(4.2-integer1);

> fraction2 = 100*(2.35-integer2);

>

> result1 = integer1/integer2;

> result2 = fraction1/fraction2;

>

> final = result1+(result2/100);

>

> R. Williams

>

> ---------- Original Message -----------

> From: mayank agarwal

> To: "c..."

> Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

> Subject: [c6x] Floating point division

>

> > Hi

> >

> > how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> > separately the integer part and the fractional part and combine the result.

> >

> > Regards,

> > Mayank

> ------- End of Original Message -------

------- End of Original Message -------

_____________________________________

with float a; and float b:

you should be able to simply say.

float c = a/b;

then the compiler will perform the math using floating point.

Note;

if the DSP is fixed point, then you will need to include a floating point

library, both at compile time '#include ' and '#include '

and at link time '-lm'

Note:

The floating point libraries are very large.

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: Richard Williams

Cc: "c..."

Sent: Sat, 6 Apr 2013 08:23:40 -0700 (PDT)

Subject: Re: [c6x] Floating point division

> Hi Richard,

>

> Thanks for your mail.The problem is like that gien below.

>

> Let's say, I give you a function called div_int which takes two

> integer arguments, x and y and gives a result which is the integer

> divisionof the two numbers. E.g. if x = 4 and y = 2 the answer is 2.

> If x = 5 and y = 2 the answer is 2. If x = 10 and y = 3 the answer is

> 3 etc.

>

> How will you use this div_int function to compute floating point divisions?

>

> Here is part of the C-code

>

> void main(void)

> {

> float a = 0.1;

> float b = 0.2; // Do the same thing with a = 4.2 and b = 2.35

>

> // fill in the blanks

> _____;

> .

> .

> .

> _____;

> __ = div_int(__, __); // fill in the blanks

>

> // fill in some more blanks

> ______;

> .

> .

> .

> ______;

>

> printf("The integer part of the divisionis %d and the fractional

> part of the divisionis %d\n", __, __); // fill in the blanks }

>

> Thanks and Regards

> Mayank

>

> ________________________________

> From: Richard Williams

> To: mayank agarwal ; "c..."

> Sent: Saturday, April 6, 2013 8:40 PM Subject:

> Re: [c6x] Floating point division

>

> Mayank,

>

> Perhaps if you explained why you are wanting to handle the integer and

> fractional part separately, we could be of more help.

>

> Are you actually trying to perform Fixed Point math?

>

> The following code performs that you say you are asking for, but the

> result is meaningless:

>

> int integer1;

> int fraction1;

>

> int integer2;

> int fraction2;

>

> float result1;

> float result2:

>

> float integer3;

> float integer4

>

> float final;

>

> integer1 = floor(4.2);

> integer2 = floor(2.35);

>

> fraction1 = 100*(4.2-integer1);

> fraction2 = 100*(2.35-integer2);

>

> result1 = integer1/integer2;

> result2 = fraction1/fraction2;

>

> final = result1+(result2/100);

>

> R. Williams

>

> ---------- Original Message -----------

> From: mayank agarwal

> To: "c..."

> Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

> Subject: [c6x] Floating point division

>

> > Hi

> >

> > how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> > separately the integer part and the fractional part and combine the result.

> >

> > Regards,

> > Mayank

> ------- End of Original Message -------

------- End of Original Message -------

_____________________________________

Reply by ●April 6, 20132013-04-06

> Subject: Floating point division

> Posted by: "mayank agarwal" m...@yahoo.com

> Date: Fri Apr 5, 2013 9:30 pm ((PDT))

>

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

> integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

>

Hi Mayank,

You might want to scale up the numbers so that both are integers and

keep the exponent in mind to scale down the result.

Rgds,

Andrew

_____________________________________

> Posted by: "mayank agarwal" m...@yahoo.com

> Date: Fri Apr 5, 2013 9:30 pm ((PDT))

>

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

> integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

>

Hi Mayank,

You might want to scale up the numbers so that both are integers and

keep the exponent in mind to scale down the result.

Rgds,

Andrew

_____________________________________

Reply by ●April 7, 20132013-04-07

Hi

Could you please illustrate floating point division using a/b where a = 4.2 and b=3.5

Regards

Mayank

________________________________

From: Andrew Nesterov

To: c...

Cc: mayank agarwal

Sent: Sunday, April 7, 2013 1:08 AM

Subject: [c6x] Re: Floating point division

> Subject: Floating point division

> Posted by: "mayank agarwal" m...@yahoo.com

> Date: Fri Apr 5, 2013 9:30 pm ((PDT))

>

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

> integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

>

Hi Mayank,

You might want to scale up the numbers so that both are integers and

keep the exponent in mind to scale down the result.

Rgds,

Andrew

Could you please illustrate floating point division using a/b where a = 4.2 and b=3.5

Regards

Mayank

________________________________

From: Andrew Nesterov

To: c...

Cc: mayank agarwal

Sent: Sunday, April 7, 2013 1:08 AM

Subject: [c6x] Re: Floating point division

> Subject: Floating point division

> Posted by: "mayank agarwal" m...@yahoo.com

> Date: Fri Apr 5, 2013 9:30 pm ((PDT))

>

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

> integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

>

Hi Mayank,

You might want to scale up the numbers so that both are integers and

keep the exponent in mind to scale down the result.

Rgds,

Andrew

Reply by ●April 7, 20132013-04-07

Hi Richard,

Thanks for your mail.The problem is like that gien below.

Let's say, I give you a function called div_int which takes two integer arguments, x and y and gives a result which is the integer divisionof the two numbers. E.g. if x = 4 and y = 2 the answer is 2. If x = 5 and y = 2 the answer is 2. If x = 10 and y = 3 the answer is 3 etc.

How will you use this div_int function to compute floating point divisions?

Here is part of the C-code

void main(void)

{

float a = 0.1;

float b = 0.2; // Do the same thing with a = 4.2 and b = 2.35

// fill in the blanks

_____;

.

.

.

_____;

__ = div_int(__, __); // fill in the blanks

// fill in some more blanks

______;

.

.

.

______;

printf("The integer part of the divisionis %d and the fractional part of the divisionis %d\n", __, __); // fill in the blanks

}

Thanks and Regards

Mayank

________________________________

From: Richard Williams

To: mayank agarwal ; "c..."

Sent: Saturday, April 6, 2013 8:40 PM

Subject: Re: [c6x] Floating point division

Mayank,

Perhaps if you explained why you are wanting to handle the integer and

fractional part separately, we could be of more help.

Are you actually trying to perform Fixed Point math?

The following code performs that you say you are asking for, but the result is

meaningless:

int integer1;

int fraction1;

int integer2;

int fraction2;

float result1;

float result2:

float integer3;

float integer4

float final;

integer1 = floor(4.2);

integer2 = floor(2.35);

fraction1 = 100*(4.2-integer1);

fraction2 = 100*(2.35-integer2);

result1 = integer1/integer2;

result2 = fraction1/fraction2;

final = result1+(result2/100);

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: "c..."

Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

Subject: [c6x] Floating point division

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> separately the integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

------- End of Original Message -------

Thanks for your mail.The problem is like that gien below.

Let's say, I give you a function called div_int which takes two integer arguments, x and y and gives a result which is the integer divisionof the two numbers. E.g. if x = 4 and y = 2 the answer is 2. If x = 5 and y = 2 the answer is 2. If x = 10 and y = 3 the answer is 3 etc.

How will you use this div_int function to compute floating point divisions?

Here is part of the C-code

void main(void)

{

float a = 0.1;

float b = 0.2; // Do the same thing with a = 4.2 and b = 2.35

// fill in the blanks

_____;

.

.

.

_____;

__ = div_int(__, __); // fill in the blanks

// fill in some more blanks

______;

.

.

.

______;

printf("The integer part of the divisionis %d and the fractional part of the divisionis %d\n", __, __); // fill in the blanks

}

Thanks and Regards

Mayank

________________________________

From: Richard Williams

To: mayank agarwal ; "c..."

Sent: Saturday, April 6, 2013 8:40 PM

Subject: Re: [c6x] Floating point division

Mayank,

Perhaps if you explained why you are wanting to handle the integer and

fractional part separately, we could be of more help.

Are you actually trying to perform Fixed Point math?

The following code performs that you say you are asking for, but the result is

meaningless:

int integer1;

int fraction1;

int integer2;

int fraction2;

float result1;

float result2:

float integer3;

float integer4

float final;

integer1 = floor(4.2);

integer2 = floor(2.35);

fraction1 = 100*(4.2-integer1);

fraction2 = 100*(2.35-integer2);

result1 = integer1/integer2;

result2 = fraction1/fraction2;

final = result1+(result2/100);

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: "c..."

Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

Subject: [c6x] Floating point division

> Hi

>

> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> separately the integer part and the fractional part and combine the result.

>

> Regards,

> Mayank

------- End of Original Message -------

Reply by ●April 7, 20132013-04-07

mayank,

If I understand you correctly, you want to perform an integer division (on

integers), and display both the result and the remainder.

For positive integers...

int a,b, result, remainder;

a=???

b=???

result = a / b;

remainder = a % b;

for negative integers (one or both)

int count = 0;

result = a / b;

if ( a < 0 )

{

count++;

a *= -1;

}

if ( b < 0 )

{

count++;

b *= -1;

}

remainder = a % b;

if ( count&0x01 ) remainder *= -1;

To perform the same kind of action on float values.

first decide how many decimal places to keep, lets use 3 decimal places

int a_int = floor(a*1000.0);

int b_int = floor(b*1000.0);

result = a_int / b_int;

remainder = a_int % b_int;

You could divide 'remainder' by 1000.0 to get the original leftover amount.

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: Richard Williams

Cc: "c..."

Sent: Sat, 6 Apr 2013 08:23:40 -0700 (PDT)

Subject: Re: [c6x] Floating point division

> Hi Richard,

>

> Thanks for your mail.The problem is like that gien below.

>

> Let's say, I give you a function called div_int which takes two

> integer arguments, x and y and gives a result which is the integer

> divisionof the two numbers. E.g. if x = 4 and y = 2 the answer is 2.

> If x = 5 and y = 2 the answer is 2. If x = 10 and y = 3 the answer is

> 3 etc.

>

> How will you use this div_int function to compute floating point divisions?

>

> Here is part of the C-code

>

> void main(void)

> {

> float a = 0.1;

> float b = 0.2; // Do the same thing with a = 4.2 and b = 2.35

>

> // fill in the blanks

> _____;

> .

> .

> .

> _____;

> __ = div_int(__, __); // fill in the blanks

>

> // fill in some more blanks

> ______;

> .

> .

> .

> ______;

>

> printf("The integer part of the divisionis %d and the fractional

> part of the divisionis %d\n", __, __); // fill in the blanks }

>

> Thanks and Regards

> Mayank

>

> ________________________________

> From: Richard Williams

> To: mayank agarwal ; "c..."

> Sent: Saturday, April 6, 2013 8:40 PM Subject:

> Re: [c6x] Floating point division

>

> Mayank,

>

> Perhaps if you explained why you are wanting to handle the integer and

> fractional part separately, we could be of more help.

>

> Are you actually trying to perform Fixed Point math?

>

> The following code performs that you say you are asking for, but the

> result is meaningless:

>

> int integer1;

> int fraction1;

>

> int integer2;

> int fraction2;

>

> float result1;

> float result2:

>

> float integer3;

> float integer4

>

> float final;

>

> integer1 = floor(4.2);

> integer2 = floor(2.35);

>

> fraction1 = 100*(4.2-integer1);

> fraction2 = 100*(2.35-integer2);

>

> result1 = integer1/integer2;

> result2 = fraction1/fraction2;

>

> final = result1+(result2/100);

>

> R. Williams

>

> ---------- Original Message -----------

> From: mayank agarwal

> To: "c..."

> Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

> Subject: [c6x] Floating point division

>

> > Hi

> >

> > how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> > separately the integer part and the fractional part and combine the result.

> >

> > Regards,

> > Mayank

> ------- End of Original Message -------

------- End of Original Message -------

_____________________________________

If I understand you correctly, you want to perform an integer division (on

integers), and display both the result and the remainder.

For positive integers...

int a,b, result, remainder;

a=???

b=???

result = a / b;

remainder = a % b;

for negative integers (one or both)

int count = 0;

result = a / b;

if ( a < 0 )

{

count++;

a *= -1;

}

if ( b < 0 )

{

count++;

b *= -1;

}

remainder = a % b;

if ( count&0x01 ) remainder *= -1;

To perform the same kind of action on float values.

first decide how many decimal places to keep, lets use 3 decimal places

int a_int = floor(a*1000.0);

int b_int = floor(b*1000.0);

result = a_int / b_int;

remainder = a_int % b_int;

You could divide 'remainder' by 1000.0 to get the original leftover amount.

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: Richard Williams

Cc: "c..."

Sent: Sat, 6 Apr 2013 08:23:40 -0700 (PDT)

Subject: Re: [c6x] Floating point division

> Hi Richard,

>

> Thanks for your mail.The problem is like that gien below.

>

> Let's say, I give you a function called div_int which takes two

> integer arguments, x and y and gives a result which is the integer

> divisionof the two numbers. E.g. if x = 4 and y = 2 the answer is 2.

> If x = 5 and y = 2 the answer is 2. If x = 10 and y = 3 the answer is

> 3 etc.

>

> How will you use this div_int function to compute floating point divisions?

>

> Here is part of the C-code

>

> void main(void)

> {

> float a = 0.1;

> float b = 0.2; // Do the same thing with a = 4.2 and b = 2.35

>

> // fill in the blanks

> _____;

> .

> .

> .

> _____;

> __ = div_int(__, __); // fill in the blanks

>

> // fill in some more blanks

> ______;

> .

> .

> .

> ______;

>

> printf("The integer part of the divisionis %d and the fractional

> part of the divisionis %d\n", __, __); // fill in the blanks }

>

> Thanks and Regards

> Mayank

>

> ________________________________

> From: Richard Williams

> To: mayank agarwal ; "c..."

> Sent: Saturday, April 6, 2013 8:40 PM Subject:

> Re: [c6x] Floating point division

>

> Mayank,

>

> Perhaps if you explained why you are wanting to handle the integer and

> fractional part separately, we could be of more help.

>

> Are you actually trying to perform Fixed Point math?

>

> The following code performs that you say you are asking for, but the

> result is meaningless:

>

> int integer1;

> int fraction1;

>

> int integer2;

> int fraction2;

>

> float result1;

> float result2:

>

> float integer3;

> float integer4

>

> float final;

>

> integer1 = floor(4.2);

> integer2 = floor(2.35);

>

> fraction1 = 100*(4.2-integer1);

> fraction2 = 100*(2.35-integer2);

>

> result1 = integer1/integer2;

> result2 = fraction1/fraction2;

>

> final = result1+(result2/100);

>

> R. Williams

>

> ---------- Original Message -----------

> From: mayank agarwal

> To: "c..."

> Sent: Fri, 5 Apr 2013 21:09:22 -0700 (PDT)

> Subject: [c6x] Floating point division

>

> > Hi

> >

> > how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide

> > separately the integer part and the fractional part and combine the result.

> >

> > Regards,

> > Mayank

> ------- End of Original Message -------

------- End of Original Message -------

_____________________________________

Reply by ●April 7, 20132013-04-07

mayank,

your might want to google some examples of floating point division.

For instance,

when you go to the following, there are several side bar items regarding things

that need to be taken into account.

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: Andrew Nesterov

Cc: "c..."

Sent: Sat, 6 Apr 2013 12:55:40 -0700 (PDT)

Subject: Re: [c6x] Re: Floating point division

> Hi

>

> Could you please illustrate floating point division using a/b where a

> = 4.2 and b=3.5 Regards Mayank

>

> ________________________________

> From: Andrew Nesterov

> To: c...

> Cc: mayank agarwal

> Sent: Sunday, April 7, 2013 1:08 AM

> Subject: [c6x] Re: Floating point division

>

>

>

> > Subject: Floating point division

> > Posted by: "mayank agarwal" m...@yahoo.com

> > Date: Fri Apr 5, 2013 9:30 pm ((PDT))

> >

> > Hi

> >

> > how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

> > integer part and the fractional part and combine the result.

> >

> > Regards,

> > Mayank

> > Hi Mayank,

>

> You might want to scale up the numbers so that both are integers and

> keep the exponent in mind to scale down the result.

>

> Rgds,

>

> Andrew

------- End of Original Message -------

_____________________________________

your might want to google some examples of floating point division.

For instance,

when you go to the following, there are several side bar items regarding things

that need to be taken into account.

R. Williams

---------- Original Message -----------

From: mayank agarwal

To: Andrew Nesterov

Cc: "c..."

Sent: Sat, 6 Apr 2013 12:55:40 -0700 (PDT)

Subject: Re: [c6x] Re: Floating point division

> Hi

>

> Could you please illustrate floating point division using a/b where a

> = 4.2 and b=3.5 Regards Mayank

>

> ________________________________

> From: Andrew Nesterov

> To: c...

> Cc: mayank agarwal

> Sent: Sunday, April 7, 2013 1:08 AM

> Subject: [c6x] Re: Floating point division

>

>

>

> > Subject: Floating point division

> > Posted by: "mayank agarwal" m...@yahoo.com

> > Date: Fri Apr 5, 2013 9:30 pm ((PDT))

> >

> > Hi

> >

> > how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

> > integer part and the fractional part and combine the result.

> >

> > Regards,

> > Mayank

> > Hi Mayank,

>

> You might want to scale up the numbers so that both are integers and

> keep the exponent in mind to scale down the result.

>

> Rgds,

>

> Andrew

------- End of Original Message -------

_____________________________________

Reply by ●April 8, 20132013-04-08

> Date: 06-Apr-2013 12:55:40 -0700

> Cc: "c..."

> Subject: Re: [c6x] Re: Floating point division

>

> Hi

>

> Could you please illustrate floating point division using a/b where a = 4.2 and b=3.5

I mean that simple scaling: 4.2/3.5 = 42/35 (both scaled up by 10^1, result is

intact). Another example would be 4.2/0.35 = (42*10^(-1))/(35*10^(-2)) 42/35*10^1. It would be simplier to scale the numbers with powers of 2 being in

the binary format, such as IEEE-754.

Rgds,

Andrew

> Regards

> Mayank

> ________________________________

> From: Andrew Nesterov

> To: c...

> Cc: mayank agarwal

> Sent: Sunday, April 7, 2013 1:08 AM

> Subject: [c6x] Re: Floating point division

>> Subject: Floating point division

>> Posted by: "mayank agarwal" m...@yahoo.com

>> Date: Fri Apr 5, 2013 9:30 pm ((PDT))

>>

>> Hi

>>

>> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

>> integer part and the fractional part and combine the result.

>>

>> Regards,

>> Mayank

>> Hi Mayank,

>

> You might want to scale up the numbers so that both are integers and

> keep the exponent in mind to scale down the result.

>

> Rgds,

>

> Andrew

_____________________________________

> Cc: "c..."

> Subject: Re: [c6x] Re: Floating point division

>

> Hi

>

> Could you please illustrate floating point division using a/b where a = 4.2 and b=3.5

I mean that simple scaling: 4.2/3.5 = 42/35 (both scaled up by 10^1, result is

intact). Another example would be 4.2/0.35 = (42*10^(-1))/(35*10^(-2)) 42/35*10^1. It would be simplier to scale the numbers with powers of 2 being in

the binary format, such as IEEE-754.

Rgds,

Andrew

> Regards

> Mayank

> ________________________________

> From: Andrew Nesterov

> To: c...

> Cc: mayank agarwal

> Sent: Sunday, April 7, 2013 1:08 AM

> Subject: [c6x] Re: Floating point division

>> Subject: Floating point division

>> Posted by: "mayank agarwal" m...@yahoo.com

>> Date: Fri Apr 5, 2013 9:30 pm ((PDT))

>>

>> Hi

>>

>> how to divide two numbers.e,g if a = 4.2,b=2.35 how to divide separately the

>> integer part and the fractional part and combine the result.

>>

>> Regards,

>> Mayank

>> Hi Mayank,

>

> You might want to scale up the numbers so that both are integers and

> keep the exponent in mind to scale down the result.

>

> Rgds,

>

> Andrew

_____________________________________