On Mon, 14 Nov 2005 15:55:05 -0500, Jerry Avins <jya@ieee.org> wrote:>robert bristow-johnson wrote: >> in article GZudnR-nuJ1iBuXeRVn-rQ@rcn.net, Jerry Avins at jya@ieee.org wrote >> on 11/14/2005 09:15: >> >> >>>robert bristow-johnson wrote: >>> >>>>in article AaadnfuiMfkDneXenZ2dnUVZ_sudnZ2d@rcn.net, Jerry Avins at >>>>jya@ieee.org wrote on 11/13/2005 22:12: >>>> >>>> >>>> >>>>>A Gray code is one in which -- with a single exception -- codes for >>>>>adjacent states differ by only one bit. >>>> >>>> >>>>??? >>>> >>>>what's that single exception, Jerry? >>> >>>Wraparound. >> >> >> but, i think even in that case, there is only one bit changing when you >> change to neighboring states, including a wrapped around state. the first i >> ever learned about Gray code was with mechanical shaft encoders. in fact, >> the quadrature shaft encoder that at least the older mice and trackballs >> used, were a two bit Gray code. > >I agree that there is no exception if states on opposite sides of >wraparound are considered adjacent.Forgive me for being pedantic but even if states on opposite sides of wraparound are not considered adjacent there is no exception. If they are not adjacent there is no state to the right of 7 and no state to the left of 0 so the whole question of difference between states becomes moot. Anyway as a hardware designer, it never occured to me to question the adjacency issue as in 3 bit binary 7+1 = 0 just as naturally as 1+2=3. As far as I am considered they are adjacent by definition not by choice.
Continuous-time DSP with no sampling
Started by ●November 2, 2005
Reply by ●November 14, 20052005-11-14
Reply by ●November 14, 20052005-11-14
mk wrote: ...> Forgive me for being pedantic but even if states on opposite sides of > wraparound are not considered adjacent there is no exception. If they > are not adjacent there is no state to the right of 7 and no state to > the left of 0 so the whole question of difference between states > becomes moot. > Anyway as a hardware designer, it never occured to me to question the > adjacency issue as in 3 bit binary 7+1 = 0 just as naturally as 1+2=3. > As far as I am considered they are adjacent by definition not by > choice.OK. I'll buy that. I wanted to avoid a categorical statement and created more trouble than I might have avoided. Jerry -- Engineering is the art of making what you want from things you can get. �����������������������������������������������������������������������
Reply by ●November 15, 20052005-11-15
in article LOmdnaADz_YPyuTeRVn-gg@rcn.net, Jerry Avins at jya@ieee.org wrote on 11/14/2005 22:35:> mk wrote: > > ... > >> Forgive me for being pedantic but even if states on opposite sides of >> wraparound are not considered adjacent there is no exception. If they >> are not adjacent there is no state to the right of 7 and no state to >> the left of 0 so the whole question of difference between states >> becomes moot. >> Anyway as a hardware designer, it never occured to me to question the >> adjacency issue as in 3 bit binary 7+1 = 0 just as naturally as 1+2=3. >> As far as I am considered they are adjacent by definition not by >> choice. > > OK. I'll buy that. I wanted to avoid a categorical statement and created > more trouble than I might have avoided.that'll teach ya! (hee-hee-hee-hee-hee) actually, by even bringing up Gray code in the conceptual A/D (for the same reason, i thought if i didn't put in that caveat, someone else would nail me for it), the same thing happened to me. -- r b-j rbj@audioimagination.com "Imagination is more important than knowledge."
