Hello I have two unknown speech sources s1 and s2 and one observation y: y[k]=c1*s1[k]+c2*s2[k]; where c1 and c2 are constants. Where can I download a matlab algorithm that performs source separation for under-determined (under-complete) systems ? I need some matlab algorithm which is able to estimate s1 and s2 based on y. Thanks in advance...
MATLABS algorithm for underdetermined (blind) source separation. Where to download?
Started by ●November 7, 2005
Reply by ●November 9, 20052005-11-09
Did you find anything? I've been looking for the same thing. Richard Lars Hansen wrote:> Hello > > I have two unknown speech sources s1 and s2 and one observation y: > > y[k]=c1*s1[k]+c2*s2[k]; > > where c1 and c2 are constants. > > Where can I download a matlab algorithm that performs source separation > for under-determined (under-complete) systems ? I need some matlab algorithm > which is able to estimate s1 and s2 based on y. > > Thanks in advance... > > >
Reply by ●November 9, 20052005-11-09
> I have two unknown speech sources s1 and s2 and one observation y: > > y[k]=c1*s1[k]+c2*s2[k]; > > where c1 and c2 are constants. > > Where can I download a matlab algorithm that performs source separation > for under-determined (under-complete) systems ? > I need some matlab > algorithm which is able to estimate s1 and s2 based on y.Homework for a community college class ? Must be pretty advanced community college :-)
Reply by ●November 11, 20052005-11-11
Nope...not so far...it's probably impossible...Maybe some statistical approach is the answer....in my case the two source signals s1 and s2 are correlated: y[k]=a*s1[k]+b*s2[k] where a,b are unknown constants and s2[k]=unknown function of s1[k] So maybe the correlation can be used for something?> Did you find anything? I've been looking for the same thing.
Reply by ●November 11, 20052005-11-11
Reply by ●November 11, 20052005-11-11
thanks for the link, but I don't see any code/paper dealing with the problem I am trying to solve? ------------- "spasmous" <spasmous@yahoo.com> skrev i en meddelelse news:1131736652.625835.38960@g43g2000cwa.googlegroups.com...> Did you try looking on the internet? Sheesh... > > http://www.tsi.enst.fr/~cardoso/guidesepsou.html >
Reply by ●November 11, 20052005-11-11